72 In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6961 subjects randomly selected from an online group involved with ears. There were 1306 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA M₂: p=02 H₂:p<02 OC. H₂p#02 H₂:p=02 OE H₂:p>02 H₁: p=0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is less than the significance level, greater than the null hypothesis. There is reject fail to reject sufficient OB. Ho: p=0.2 H₂:p*0.2 insufficient OD. Ho: p=0.2 H₁: p>0.2 evidence to support the claim that the retum rate is less than 20%. OF. Ho:p<0.2 H₁: p=0.2 This questo

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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72
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6961 subjects randomly selected from an online group involved with ears. There were 1306 surveys retumed. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value
method and use the normal distribution as an approximation to the binomial distribution.
Identify the null hypothesis and alternative hypothesis.
OA H₂: p=0.2
H₁: p<0.2
OC. Ho: p*0.2
H₁: p=0.2
OE. Ho:p>0.2
H₁: p=0.2
The test statistic is z=
(Round to two decimal places as needed.)
The P-value is
(Round to three decimal places as needed.)
Because the P-value is
less than
the significance level,
greater than
the null hypothesis. There is
reject
fail to reject
sufficient
OB. Ho: p=0.2
H₁: p=0.2
insufficient
OD. Ho: p=0.2
H₁: p>0.2
evidence to support the claim that the return rate is less than 20%.
OF. Ho: p<0.2
H₁: p=0.2
This quest
Transcribed Image Text:72 In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6961 subjects randomly selected from an online group involved with ears. There were 1306 surveys retumed. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA H₂: p=0.2 H₁: p<0.2 OC. Ho: p*0.2 H₁: p=0.2 OE. Ho:p>0.2 H₁: p=0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is less than the significance level, greater than the null hypothesis. There is reject fail to reject sufficient OB. Ho: p=0.2 H₁: p=0.2 insufficient OD. Ho: p=0.2 H₁: p>0.2 evidence to support the claim that the return rate is less than 20%. OF. Ho: p<0.2 H₁: p=0.2 This quest
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