72 g of CaCO3 is treated with 0.500 L of a 1.00M solution of HCl. What volume of CO2 gas, measured at 25˚C and 795. mm Hg can be obtained? CaCO3(s) + 2HCl(aq) ----> CO2(g) + CaCl2(aq) + H2O(l) Show all equation and all calculations involved to get full marks. Hint: this is a limiting type question! Use the following questions as a guide and include them in your answer. the limiting reactant is? the maximum number of moles of CO2 gas that can be produced is? the volume of CO2 gas that can be produced from this reaction is?
72 g of CaCO3 is treated with 0.500 L of a 1.00M solution of HCl. What volume of CO2 gas, measured at 25˚C and 795. mm Hg can be obtained? CaCO3(s) + 2HCl(aq) ----> CO2(g) + CaCl2(aq) + H2O(l) Show all equation and all calculations involved to get full marks. Hint: this is a limiting type question! Use the following questions as a guide and include them in your answer. the limiting reactant is? the maximum number of moles of CO2 gas that can be produced is? the volume of CO2 gas that can be produced from this reaction is?
Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.107E
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72 g of CaCO3 is treated with 0.500 L of a 1.00M solution of HCl. What volume of CO2 gas, measured at 25˚C and 795. mm Hg can be obtained?
CaCO3(s) + 2HCl(aq) ----> CO2(g) + CaCl2(aq) + H2O(l)
Show all equation and all calculations involved to get full marks. Hint: this is a limiting type
question!
Use the following questions as a guide and include them in your answer.
- the limiting reactant is?
- the maximum number of moles of CO2 gas that can be produced is?
- the volume of CO2 gas that can be produced from this reaction is?
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