7.35 LAB: Exception handling to detect input String vs. Integer The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age.Ex: If the input is:Lee 18 Lua 21 Mary Beth 19 Stu 33 -1then the output is:Lee 19 Lua 22 Mary 0 Stu 34 17ਰਜਰ18192021 }}}inputName=scnr.next(); LABACTIVITY13141 import java.util.Scanner;2 import java.util. InputMismatchException;34 public class NameAgeChecker {5 public static void main(String[] args) {6Scanner scnr = new Scanner(System.in);789101112N97.35.1: LAB: Exception handling to detect input String vs. Integer1516String inputName;int age;NameAgeChecker.javainputName scnr.next();while (!inputName.equals("-1")) {// FIXME: The following line will throw an InputMismatchException.Insert a try/catch statement to catch the exception.age = scnr.nextInt();System.out.println(inputName + + (age + 1));0/10Load default template...

I have done the code using Java.

7.35 LAB: Exception handling to detect input String vs. Integer The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The progra

7.35 LAB: Exception handling to detect input String vs. Integer The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The progra

Programming Logic & Design Comprehensive

9th Edition

ISBN:9781337669405

Author:FARRELL

Publisher:FARRELL

Chapter11: More Object-oriented Programming Concepts

Section: Chapter Questions

Problem 20RQ

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7.35 LAB: Exception handling to detect input String vs. Integer

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age.

Ex: If the input is:

Lee 18 Lua 21 Mary Beth 19 Stu 33 -1

then the output is:

Lee 19 Lua 22 Mary 0 Stu 34

17
ਰਜਰ
18
19
20
21 }
}
}
inputName
=
scnr.next();

LAB
ACTIVITY
13
14
1 import java.util.Scanner;
2 import java.util. InputMismatchException;
3
4 public class NameAgeChecker {
5 public static void main(String[] args) {
6
Scanner scnr = new Scanner(System.in);
7
8
9
10
11
12
N9
7.35.1: LAB: Exception handling to detect input String vs. Integer
15
16
String inputName;
int age;
NameAgeChecker.java
inputName scnr.next();
while (!inputName.equals("-1")) {
// FIXME: The following line will throw an InputMismatchException.
Insert a try/catch statement to catch the exception.
age = scnr.nextInt();
System.out.println(inputName + + (age + 1));
0/10
Load default template...

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