63.45 mL of 0.250 M Ba(OH)2 reacts with 0.750 M HNO3 and reaches the endpoint using phenolphthalein as an indicator. What volume of HNO3 is required for this reaction? Ba(NO3)2 + 2H₂O 2HNO3 + Ba(OH)2 2 →

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter20: Chemistry Of The Metals
Section: Chapter Questions
Problem 42QAP: Rust, which you can take to be Fe(OH)3, can be dissolved by treating it with oxalic acid. An...
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63.45 mL of 0.250 M Ba(OH)2 reacts
with 0.750 M HNO3 and reaches the
endpoint using phenolphthalein as an
indicator. What volume of HNO3 is
required for this reaction?
2HNO3 + Ba(OH)2 → Ba(NO3)2 + 2H₂O
[?] mL HNO3
mL HNO
Enter
Transcribed Image Text:63.45 mL of 0.250 M Ba(OH)2 reacts with 0.750 M HNO3 and reaches the endpoint using phenolphthalein as an indicator. What volume of HNO3 is required for this reaction? 2HNO3 + Ba(OH)2 → Ba(NO3)2 + 2H₂O [?] mL HNO3 mL HNO Enter
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