6.56 The standard enthalpy change for the following reaction is 436.4 kJ/mol: H₂(g) → H(g) + H(g) Calculate the standard enthalpy of formation of atomic hydrogen (H).

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 67QAP: Given the following reactions, N2H4(l)+O2(g)N2(g)+2H2O(g)H=534.2kJ H2(g)+12 O2(g)H2O(g)H=241.8kJ...
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6.56 The standard enthalpy change for the following
reaction is 436.4 kJ/mol:
H₂(g) → H(g) + H(g)
Calculate the standard enthalpy of formation of
atomic hydrogen (H).
Transcribed Image Text:6.56 The standard enthalpy change for the following reaction is 436.4 kJ/mol: H₂(g) → H(g) + H(g) Calculate the standard enthalpy of formation of atomic hydrogen (H).
Expert Solution
Step 1

The standard enthalpy change for the formation of the atomic hydrogen is given by:

H2g    Hg  + Hg  H = 436.4 kJ/molH2g    2Hg   H = 436.4 kJ/mol

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