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6. From the following heats of combustion, CH3OH) C(graphite) H2(g) + 3/2 0₂ + O2(g) + ½ O2(g) CO2(g) + 2H₂O CO2(g) H₂O(1) AH° A H° -726.4 KJ -390.5 KJ ΔΗ° = -285.8 KJ Calculate the enthalpy formation of methanol (CH3OH) from its elements.

6. From the following heats of combustion, CH3OH) C(graphite) H2(g) + 3/2 0₂ + O2(g) + ½ O2(g) CO2(g) + 2H₂O CO2(g) H₂O(1) AH° A H° -726.4 KJ -390.5 KJ ΔΗ° = -285.8 KJ Calculate the enthalpy formation of methanol (CH3OH) from its elements.

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.27QE
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6. From the following heats of combustion, CH3OH) C(graphite) H2(g) + 3/2 0₂ + O2(g) C(graphite) + ½ O2(g) CO2(g) + 2H₂O CO2(g) 2H₂ +1/202 H₂0 (1) Calculate the enthalpy formation of methanol (CH3OH) from its elements. A H° A H° CH3OH) -726.4 KJ -390.5 KJ ΔΗ° = -285.8 KJ
Transcribed Image Text:6. From the following heats of combustion, CH3OH) C(graphite) H2(g) + 3/2 0₂ + O2(g) C(graphite) + ½ O2(g) CO2(g) + 2H₂O CO2(g) 2H₂ +1/202 H₂0 (1) Calculate the enthalpy formation of methanol (CH3OH) from its elements. A H° A H° CH3OH) -726.4 KJ -390.5 KJ ΔΗ° = -285.8 KJ
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