6. Calculate Kc for2N204(6) + 3021e) - 2N20 (e) K=?using..Reaction 12N2e) + O2le)- 2N,0 (2)K, = 1.2 x 10352NO2 (6)K2 = 4.6 x 103Reaction 2½ N21e) + O218)e NO2 (2)K3 = 4.1 x 10°Reaction 3

Given: 2N2g+O2g⇌2N2Og; K1=1.2×10-35 ......(1)N2O4g⇌2NO2g; K2=4.6×10-3 ......(2)12N2g+O2g⇌NO2g;…

6. Calculate Kc for 2N,O4e) + 30zle) → 2N,0 (2 K=? using. (E) Reaction 1 2N218) + Ozle) * 2N,0 (e) K, = 1.2 x 10 35 Reaction 2 - 2NO2 (e) K2 = 4.6 x 103 Reaction 3 ½ Nze) + O2le) → NO2(e) K3 = 4.1 x 10

6. Calculate Kc for 2N,O4e) + 30zle) → 2N,0 (2 K=? using. (E) Reaction 1 2N218) + Ozle) * 2N,0 (e) K, = 1.2 x 10 35 Reaction 2 - 2NO2 (e) K2 = 4.6 x 103 Reaction 3 ½ Nze) + O2le) → NO2(e) K3 = 4.1 x 10

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter9: Aqueous Solutions And Chemical Equilibria

Section: Chapter Questions

Problem 9.8QAP

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Question

6. Calculate Kc for
2N204(6) + 3021e) - 2N20 (e) K=?
using..
Reaction 1
2N2e) + O2le)
- 2N,0 (2)
K, = 1.2 x 1035
2NO2 (6)
K2 = 4.6 x 103
Reaction 2
½ N21e) + O218)
e NO2 (2)
K3 = 4.1 x 10°
Reaction 3

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