5.Suppose that the same recessive daf-d mutation in the N2 strain landed 20m.u. from the SNP367 locus. You cross homozygous daf-d/daf-d N2 worms to wild type HW worms, and let the hybrid F1 make gametes. How many of the gametes produced by the F1 hybrids will carry a daf-d allele and the N2 allele of SNP367 ? And how many of the gametes will carry a daf-d allele and the HW allele of SNP367, a.40% ; 10% b.20% ; 80% c.50% ; 50% d.80% ; 20% e.10% ; 40%
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- 21. A species of butterfly has three alleles for wing yellow. Explain how these results could occur. are speckled blue and orange, and 25% are following offspring result: about 25% are blue color: blue, orange, and pale yellow. A blue Why don't offspring always will th s codominance nance? hey neight is a enotypes. APLY Why don't offspring alwave 2 look like their parents? THE BI асcount wer. itane butterfly mates with an orange butterfly. The and 25% are orange. However, another 25% Josie's sie s she Offspring of blue butterfly and orange butterflyAnother gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
- In sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive allele for red flowers (p). An allele for Jang pollen grains (L) is dominant when paired with a recessive allele for round pollen grains (L). Bateson and Punnett crossed a plant having purple flowers and long pollen grains with one having white flowers and round pollen grains. All F1 offspring have purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple /lower/ round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?I. Male Drosophila from a true-breeding wild-typestock were irradiated with X-rays and then mated withfemales from a true-breeding stock carrying the following recessive mutations on the X chromosome:yellow body (y), crossveinless wings (cv), cut wings(ct), singed bristles (sn), and miniature wings (m).These markers are known to map in the order:y - cv - ct - sn - mMost of the female progeny of this cross were phenotypically wild type, but one female exhibited ct and snphenotypes. When this exceptional ct sn female wasmated with a male from the true-breeding wild-typestock, twice as many females as males appearedamong the progeny.a. What is the nature of the X-ray-induced mutationpresent in the exceptional female?b. Draw the X chromosomes present in the exceptional ct sn female as they would appear duringpairing in meiosis.c. What phenotypic classes would you expect to seeamong the progeny produced by mating the exceptional ct sn female with a normal male from a truebreeding wild-type…6. A diploid strain of yeast was made by mating a haploidstrain with a genotype w−, x−, y−, and z− with a haploidstrain of opposite mating type that is wild type for thesefour genes. The diploid strain was phenotypically wildtype. Four different X-ray-induced diploid mutantswith the following phenotypes were produced fromthis diploid yeast strain. Assume a single new mutation is present in each strain.Strain 1 w− x+ y− z+Strain 2 w+ x− y− z−Strain 3 w− x+ y− z−Strain 4 w− x+ y+ z+When these mutant diploid strains of yeast go throughmeiosis, each ascus is found to contain only two viablehaploid spores.a. What kind of mutations were induced by X-rays tomake the listed diploid strains?b. Why did two spores in each ascus die?
- An individual has the following genotype. Gene loci (A) and (B) are 15 m.u. apart. What are the correct frequencies of some of the gametes that car be made by this individual? Bl a O A. Ab = 7.5%; AB = 42.5% B. ab = 25%; aB = 50% O C. AB = 7.5%; aB = 42.5% O D. aB = 15%; Ab = F0% E. aB = 70%; Ab = 15% Reset Selection OMark for Review What's This?1. In a cross between mice the genotypes AB/ab x ab/ab, what is the recombination frequency if the progeny numbers are 72 AB/ab, 68 ab/ab, 17 Ab/ab, and 21 aB/ab? The alleles are shown for each chromosome, separated by a slash (/). . 2. A cross between fruit files with genotypes Aa Bb × aa bb produces the following progeny: 10 Aa Bb 40 Aa bb 40 aa Bb 10 aa bb Were the parental alleles in the coupling or repulsion configuration? Briefly explain. 3. Briefly describe how twin studies can reveal whether or not the appearance of a trait is strongly influenced by genetics.. A diploid strain of yeast was made by mating a haploidstrain with a genotype w−, x−, y−, and z− with a haploidstrain of opposite mating type that is wild type for thesefour genes. The diploid strain was phenotypically wildtype. Four different X-ray-induced diploid mutantswith the following phenotypes were produced fromthis diploid yeast strain. Assume a single new mutation is present in each strain.Strain 1 w− x+ y− z+Strain 2 w+ x− y− z−Strain 3 w− x+ y− z−Strain 4 w− x+ y+ z+When these mutant diploid strains of yeast go throughmeiosis, each ascus is found to contain only two viablehaploid spores.a. What kind of mutations were induced by X-rays tomake the listed diploid strains?b. Why did two spores in each ascus die?c. Are any of the genes w, x, y, or z located on thesame chromosome?d. Give the order of the genes that are found on thesame chromosome
- 3. Short-tailed pup distribution. In mice, the dominant T allele results in a short tail. Homozygous T/T genotype is lethal, which means mouse embryos with this genotype die before they are born. Homozygous t/t is normal, with normal tail. A cross between two short-tailed mice produces a litter of 5 pups. a). What are the genotype(s) of the two short-tailed mice used in the cross? b). What are the possible genotypes and phenotypes of the 5 pups? What are their perspective ratio?You are a studying the genetic basis of horn color in unicorns. Gene C determines the color of pigment destined for the horn by converting a pink precursor into a purple pigment. C- individuals make purple pigment whereas cc individuals accumulate pink precursor. Gene D ensures the deposition of the pigment into the horn cells, such that D- individuals have a colored horn (purple or pink), whereas dd individuals have a white horn. You breed two purple horned unicorns to each other (CcDd). Assuming Gene C and Gene D are unlinked, what is the probability that the baby unicorn has a purple horn? Please express your answer to 2 decimal places (e.g. 0.69).13. In another species of berry, Rass berrylis, the allele for yellow fruit (F) is dominant to the allele for red fruit (f), and the allele for thorny stems (T) is dominant to the allele for thornless stems (t). The gene for fruit colour is 17.4 map units from the stem thorniness. gene for a. Draw a Punnett square to illustrate the cross between a Rass b. with red berries and thornless stems and a plant that was heterozygous for both characteristics. (The parents of the heterozygous plant were yellow-fruiting and thorny, and red- fruiting and thornless, and were homozygous for both traits.)