5. The oxidation of ferrous iron (Fe2+) to ferric ion (Fe³+) by molecular oxygen can be describe by the following reaction: 4Fe²+ (aq) + O₂(aq) + 4H*(aq) = 4Fe³+ (aq) + 2H₂O(1) (1) Using free energies of formation, calculate the equilibrium constant for this reaction at 25 deg C. (2) For a water in equilibrium with the atmosphere, a pH of 2.0, and a total soluble iron concentration of 1 mg/L, calculate the concentrations of Fe2+ (aq) and Fe³+(aq).

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Chapter13: Electrochemistry
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5. The oxidation of ferrous iron (Fe2+) to ferric ion (Fe³+) by molecular oxygen can be described
by the following reaction:
4Fe²+ (aq) + O₂(aq) + 4H*(aq) = 4Fe³+ (aq) + 2H₂O(l)
(1) Using free energies of formation, calculate the equilibrium constant for this reaction at 25
deg C.
(2) For a water in equilibrium with the atmosphere, a pH of 2.0, and a total soluble iron
concentration of 1 mg/L, calculate the concentrations of Fe2+(aq) and Fe³+(aq).
Transcribed Image Text:5. The oxidation of ferrous iron (Fe2+) to ferric ion (Fe³+) by molecular oxygen can be described by the following reaction: 4Fe²+ (aq) + O₂(aq) + 4H*(aq) = 4Fe³+ (aq) + 2H₂O(l) (1) Using free energies of formation, calculate the equilibrium constant for this reaction at 25 deg C. (2) For a water in equilibrium with the atmosphere, a pH of 2.0, and a total soluble iron concentration of 1 mg/L, calculate the concentrations of Fe2+(aq) and Fe³+(aq).
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