5. Solve Ix and all the mesh currents using mesh analysis. lov (+) 15V (+ 22 N 1₁ 62 13 72 102 :15 8 N 12 52 My Ix 14 (↑) 8A M 1452 ↓4A
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- A series RL with R = 15-02 and L = 73-H connected across a 24 VDC source for a LONG TIME, what is the voltage acroos the inductor. Write the values only (round to four decimal places).Consider the circuit below: Simplify the circuit and write the super position circuits for I1, 12, and 13 2 AZ45° 1220 v 4 AZ0° O 20 3 VZ-90°Byusing Superposition Pind the Current threg 4 Resistorof this figure. Ric24n Ea54V T Rza12 Rz=12 Ex48U R3=452
- Qs # 2. Write down the equations that results from applving Kirchhoff's junction and loop rule. A Rz 1, 7V 3v 5VFor the circuit shown below if the complex power of branch 2 is S,=1490 VA Find 1.P,Q, S, PF, for each branch 2. P7,Q7,S7,PF- 3.Draw the complete power triangle 4. Ir. I1, 12 1) IT 1 12 j4N j6 NSOLVE ALL CURRENT USING NODAL ANALYSIS. а b C Z1 Z2 Z3 Z4 V2 Z5 V1 Z6 Z7 Z1 = 1+ j2 Z5 = 5 + j6 Z6 = 6 – j7 Z7 = 7+ j8 V1 = 12 Z2 = 2 – j3 Z3 = 3 + j4 V2 = 18 Z4 = 4 – j5
- ail YouTube Maps Starting out with Py... 01 Convert-123 to sig... Binary Calculator OTwo's Complement... EL-204-D01_2023_1... book.pdf digital-fundamental... Is 492 Vs = 92-26.6°V Is = 4√2 245° A .A j492 ▬ Determine the magnitude of current lo due to the voltage source only |I₂| = Q Search Vs 4.Question 13 For the circuit shown, the following mesh currents are given: IA =1.24271.2° A IB =0.45Z49.0° A Ic = 0.75Z150.2° A What is the value of the voltage VB? j5n + 20 VB 62- 45° V j4 N VA 240° V Vc 5230° V O 2.484- 108.8° V O 2.48471.2 V O 2.23/66.8° V O 2.23Z- 113.2° Vfor the circuit shown below If v_in=5 sin2n10t then corner frequency will be Hz 1 UF 2 k Ohm 1 k Ohim 050 060 070 080 Min
- Solve the following circuit applying Kirchhoff's laws Ri Ry Rz 2K 1.5K 30V E3Draw the graph according to the circuit and choose a suitable tree. Obtain fundamental cutset equations write it in matrix form. Obtain fundamental loop equations write it in matrix form. a=1, B=9 aV 12 12 (1) BA4. Solve for I, I2, Iz and I4 in the ckt below using Cramer's Rule. ISMAT169NUMI 252 METHO 169NUMERICALIM SANDANALYSISM THOANDANALY RICLMET 169NUICA MAT169NUMERICA 幸 DDSANDA MAT169NUMERI THODSANDANALYSSMAT ANALYSISMAT 9NUM METHODSA 12V (1) I2 1 YSISMAT169N CALMETHODSANDA 351 ETHO SISMATI6 OSANDANAL RICALMETHODSAND NDAN SAND ANALYSISMAT 丰 RICAM MERICALME NDANALYSISM NUMERICAL METHOSAN SAND ALYSI METH JALYS 69NUMERI ISN I) I3 ERICALM ooDANAL TRICALMET NDANASA SMAT169NUAALYSISMAT169NUMERICALMETHODSA AT 169NU SANDA MERICLMETHODSANDA