5. Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = t 3 + cos(nt), y = 4t + sin (2t + 6); t = -3
5. Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = t 3 + cos(nt), y = 4t + sin (2t + 6); t = -3
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.3: Implicit Differentiation
Problem 26E
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