4NH3(g)  +  3O2(g)  ⇌ 2N2(g)  +  6H2O(g) If a chemist mixed 2.930 moles of ammonia (NH3) gas with 1.978 moles of oxygen (O2) gas in a 7.95 Liter airtight metal flask at 127°C and after the pressures stabilize at equilibrium and then draws an air sample and found 0.683 moles of nitrogen (N2) gas then how many moles of ammonia (NH3) is present at equilibrium?

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Chapter13: Fundamental Equilibrium Concepts
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Problem 12E: Show that the complete chemical equation, the total ionic equation, and the net ionic equation for...
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4NH3(g)  +  3O2(g)  ⇌ 2N2(g)  +  6H2O(g)

If a chemist mixed 2.930 moles of ammonia (NH3) gas with 1.978 moles of oxygen (O2) gas in a 7.95 Liter airtight metal flask at 127°C and after the pressures stabilize at equilibrium and then draws an air sample and found 0.683 moles of nitrogen (N2) gas then how many moles of ammonia (NH3) is present at equilibrium?

hitrogeni riz is sclubie in bl
N2, s Soluble in.
4NH3(g) + 302(g) = 2N2(g) + 6H2O(g)
If a chemist mixed 2.930 moles of ammonia (NH3) gas with 1.978 moles of oxygen (O2) gas in a 7.95 Liter air tight metal flask at 127°C
and after the pressures stabilizes at equilibrium and then draws an air sample and found 0.683 moles of nitrogen (N2) gas then how
many moles of ammonia (NH3) is present at equilibrium?
1.107
1.965
1.254
1.564
1.671
1.725
2.031
1.009
1.821
1.363
1.489
2.174
Transcribed Image Text:hitrogeni riz is sclubie in bl N2, s Soluble in. 4NH3(g) + 302(g) = 2N2(g) + 6H2O(g) If a chemist mixed 2.930 moles of ammonia (NH3) gas with 1.978 moles of oxygen (O2) gas in a 7.95 Liter air tight metal flask at 127°C and after the pressures stabilizes at equilibrium and then draws an air sample and found 0.683 moles of nitrogen (N2) gas then how many moles of ammonia (NH3) is present at equilibrium? 1.107 1.965 1.254 1.564 1.671 1.725 2.031 1.009 1.821 1.363 1.489 2.174
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