(4d-202) A buffer solution is made by mixing H3PO4 and NaH2PO4 in water. How does this buffer system neutralize an addition of 5 ml of 0.45 M NaOH? Choose one of the options below. • The H3PO4, as a weak acid, will neutralize the added NAOH • The NaH2P04, as a weak base, will neutralize the added NaOH • The H3PO4, as a weak base, will neutralize the added NaOH • The NaH2PO4, as a weak acid, will neutralize the added NaOH For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). U S Paragraph Arial 14px ... Q x² X, RBC v I 99 ΩΘ 田 田由田国 |

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Chapter15: Acid-base Equilibria
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Problem 3RQ: One of the most challenging parts of solving acidbase problems is writing out the correct equation....
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(4d-202) A buffer solution is made by mixing H3PO4 and NaH2PO4 in water. How does this buffer system neutralize an addition of 5
mL of 0.45 M NaOH? Choose one of the options below.
• The H3PO4, as a weak acid, will neutralize the added NaOH
• The NaH2PO4, as a weak base, will neutralize the added NaOH
• The H3PO4, as a weak base, will neutralize the added NaOH
• The NaH2PO4, as a weak acid, will neutralize the added NaOH
For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).
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Transcribed Image Text:(4d-202) A buffer solution is made by mixing H3PO4 and NaH2PO4 in water. How does this buffer system neutralize an addition of 5 mL of 0.45 M NaOH? Choose one of the options below. • The H3PO4, as a weak acid, will neutralize the added NaOH • The NaH2PO4, as a weak base, will neutralize the added NaOH • The H3PO4, as a weak base, will neutralize the added NaOH • The NaH2PO4, as a weak acid, will neutralize the added NaOH For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). Paragraph Arial 14px A v Ix Q x² X, g ST 田用国 EXE ABC <> Ť {;} +) P. O WORDS POWERED BY TINY <> +]
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