400 customers at 500 KWh/month LOAD 1 600 customers at 300 KWh /month Power Plant LOAD 2 560,000 KWh /month LOAD 3 1000 customers at 180 KWh /month Charges: 1st 100 KWh/month/customer = Php 2.12 Next 150 KWh/month/customer = Php 1.59 Next 150 Kwh/month/customer = Php 1.05 Excess from 400 KWh/month/customer = Php 0.85 Efficiency of Transmission is at 90.322% 1. The system 's monthly Energy production? 2. The production cost per month of LOAD 1 is calculated? 3. The production cost of LOAD 2 is calculated? 4. For LOAD 3 the production cost per month is?

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.12P: The voltage v(t)=359.3cos(t)volts is applied to a load consisting of a 10 resistor in parallel with...
icon
Related questions
Question

Solving problem & need solution. thanks

400 customers at 500 KWh/month
LOAD 1
600 customers at 300 KWh /month
Power Plant
LOAD 2
560,000 KWh /month
LOAD 3
1000 customers at 180 KWh /month
Charges:
I
1* 100 KWh/month/customer = Php 2.12
Next 150 KWh/month/customer = Php 1.59
Next 150 Kwh/month/customer = Php 1.05
Excess from 400 KWh/month/customer = Php 0.85
Efficiency of Transmission is at 90.322%
1. The system 's monthly Energy production?
2. The production cost per month of LOAD 1 is calculated?
3. The production cost of LOAD 2 is calculated?
4. For LOAD 3 the production cost per month is?
5. The cost per KWhr produced is taken?
Transcribed Image Text:400 customers at 500 KWh/month LOAD 1 600 customers at 300 KWh /month Power Plant LOAD 2 560,000 KWh /month LOAD 3 1000 customers at 180 KWh /month Charges: I 1* 100 KWh/month/customer = Php 2.12 Next 150 KWh/month/customer = Php 1.59 Next 150 Kwh/month/customer = Php 1.05 Excess from 400 KWh/month/customer = Php 0.85 Efficiency of Transmission is at 90.322% 1. The system 's monthly Energy production? 2. The production cost per month of LOAD 1 is calculated? 3. The production cost of LOAD 2 is calculated? 4. For LOAD 3 the production cost per month is? 5. The cost per KWhr produced is taken?
Expert Solution
steps

Step by step

Solved in 5 steps with 5 images

Blurred answer
Knowledge Booster
Differential Amplifier
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Power System Analysis and Design (MindTap Course …
Power System Analysis and Design (MindTap Course …
Electrical Engineering
ISBN:
9781305632134
Author:
J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:
Cengage Learning