4. Water is circulated from a large tank, through a filter, and back to the tank. Therequired water flowrate is 2 m?/s. Determine the power of pump (Watts).KL exit1.0KL elbow = 1.5KL valve6.0KL ent = 0.8%3DKL fiter = 12.03 cm-dia.Filter-pipe with e/D = 0.01Pump0.10.09Wholly turbulent flow0.080.070.050.040.060.030.050.020.0150.040.010.0080.0060.030.0040.0250.0020.020.0010.00080.0006Laminarflaw0.00040.015Smooth0.0002Transition range0.00010.000050.010.0090.0080.000012110')21104)4 6 B2110)6 82(106 82(10)6 84 6 84.4410101010107Re a PVD

Power of pump is, Wp = 8.224 x 1011 Watts.

4. Water is circulated from a large tank, through a filter, and back to the tank. The required water flowrate is 2 m³/s. Determine the power of pump (Watts). KL exit = 1.0 KL elbow = 1.5 KL valve = 6.0 KL filter = 12.0 KL ent = 0.8 3 cm-dia. Filter pipe with e/D = 0.01 Pump

4. Water is circulated from a large tank, through a filter, and back to the tank. The required water flowrate is 2 m³/s. Determine the power of pump (Watts). KL exit = 1.0 KL elbow = 1.5 KL valve = 6.0 KL filter = 12.0 KL ent = 0.8 3 cm-dia. Filter pipe with e/D = 0.01 Pump

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A fluid is a substance that is continuously deformed by the application of shear stress. The rate of deformation of a fluid depends on its viscosity. The fluid tries to flow when it interacts with some other system.

Question

4. Water is circulated from a large tank, through a filter, and back to the tank. The
required water flowrate is 2 m?/s. Determine the power of pump (Watts).
KL exit
1.0
KL elbow = 1.5
KL valve
6.0
KL ent = 0.8
%3D
KL fiter = 12.0
3 cm-dia.
Filter-
pipe with e/D = 0.01
Pump
0.1
0.09
Wholly turbulent flow
0.08
0.07
0.05
0.04
0.06
0.03
0.05
0.02
0.015
0.04
0.01
0.008
0.006
0.03
0.004
0.025
0.002
0.02
0.001
0.0008
0.0006
Laminar
flaw
0.0004
0.015
Smooth
0.0002
Transition range
0.0001
0.00005
0.01
0.009
0.008
0.00001
2110')
21104)
4 6 B
2110)
6 8
2(10
6 8
2(10)
6 8
4 6 8
4.
4
4
10
10
10
10
107
Re a PVD

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