4. Use the following steps to determine how to make 600 mL of a 0.1M acetate buffer, pH 5.0, using 0.1M acetic acid and 0.1M sodium acetate. a. Consider the Henderson-Hasselbalch equation. pH=pKa + log [base] [acid] Using the desired pH (5.0) and pKą of acetic acid, use the Henderson Hasselbach equation to determine a ratio of [base] [acid] required for this buffer. (For example, your answer should look something like this: [base] [acid] = 2.3 Note that this is NOT the ratio you will obtain - it is just an example) b. Given the example above, we can set [acid] = x and [base] =2.3x. Remember that the concentration of acid and base should equal the desired molarity, which 0.1. Based on this, a second equation can be obtained - given the example above, the equation would. be x + 2.3x = 0.1. Use this to solve for x, which represents the concentration of acid. ([acid]), and for [base].

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Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 14Q: Consider the following pH curves for 100.0 mL of two different acids with the same initial...
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4. Use the following steps to determine how to make 600 mL of a 0.1M acetate buffer, pH 5.0,
using 0.1M acetic acid and 0.1M sodium acetate.
a. Consider the Henderson-Hasselbalch equation.
pH =pKa+ log [base] [actd]
Using the desired pH (5.0) and pKą of acetic acid, use the Henderson Hasselbach
equation to determine a ratio of [base] [acid] required for this buffer.
(For example, your answer should look something like this: [base] [acid] =2.3
Note that this is NOT the ratio you will obtain - it is just an example)
b. Given the example above, we can set [acid] = x and [base] =2.3x. Remember that the
concentration of acid and base should equal the desired molarity, which 0.1. Based on
this, a second equation can be obtained - given the example above, the equation would.
be x + 2.3x = 0.1. Use this to solve for x, which represents the concentration of acid.
([acid]), and for [base].
Transcribed Image Text:4. Use the following steps to determine how to make 600 mL of a 0.1M acetate buffer, pH 5.0, using 0.1M acetic acid and 0.1M sodium acetate. a. Consider the Henderson-Hasselbalch equation. pH =pKa+ log [base] [actd] Using the desired pH (5.0) and pKą of acetic acid, use the Henderson Hasselbach equation to determine a ratio of [base] [acid] required for this buffer. (For example, your answer should look something like this: [base] [acid] =2.3 Note that this is NOT the ratio you will obtain - it is just an example) b. Given the example above, we can set [acid] = x and [base] =2.3x. Remember that the concentration of acid and base should equal the desired molarity, which 0.1. Based on this, a second equation can be obtained - given the example above, the equation would. be x + 2.3x = 0.1. Use this to solve for x, which represents the concentration of acid. ([acid]), and for [base].
c. Use M1V1 = M2V2 to solve for the volume of 0.1M acetic acid and 0.1M sodium acetate
required to create the buffer.
i M1 =
= 0.1M of acetic acid or 0.1M sodium acetate (stock solution)
ii. V1= what to solve for
iii. M2 = the value for [acid] or [base] solved in 4b
iv. V2 = the desired buffer volume (600mL)
Transcribed Image Text:c. Use M1V1 = M2V2 to solve for the volume of 0.1M acetic acid and 0.1M sodium acetate required to create the buffer. i M1 = = 0.1M of acetic acid or 0.1M sodium acetate (stock solution) ii. V1= what to solve for iii. M2 = the value for [acid] or [base] solved in 4b iv. V2 = the desired buffer volume (600mL)
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