Find the slope of the curve at the given x-axis coordinatePlease answer # 6 x(x+1)2x-14. y =5. f(x)6. y =Jat x = 0.61−3x+x³12at x = : 0.771(1+√1-x)²¹at xJx27.8. y = 5²x+1, at x = 0.19. y = e√x, at x = eJf(x) = √√1+ √1 − x, at x =10. y = sin (lnx²), at x =π-4114

We can find the slope of the given curve as below.

4. У y = 5. 6. y = x(x+1) 2x-1 f(x) = = at x = 0.6 1-3x+x² 13 2 at x = 0.77 1 (1+√1-x)²¹ at x = J x2 7. 8. y = 5²x+1, at x = 0.1 9. y = e√x, at x = e 10. y = sin (lnx²), at x f(x) = √√1+ √1 − x, at x = = π - 4 1 ܝܕ | ܠ 4

4. У y = 5. 6. y = x(x+1) 2x-1 f(x) = = at x = 0.6 1-3x+x² 13 2 at x = 0.77 1 (1+√1-x)²¹ at x = J x2 7. 8. y = 5²x+1, at x = 0.1 9. y = e√x, at x = e 10. y = sin (lnx²), at x f(x) = √√1+ √1 − x, at x = = π - 4 1 ܝܕ | ܠ 4

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter2: Equations And Inequalities

Section2.3: Quadratic Equations

Problem 51E

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Question

Find the slope of the curve at the given x-axis coordinate

Please answer # 6

x(x+1)
2x-1
4. y =
5. f(x)
6. y =
J
at x = 0.6
1−3x+x³
1
2
at x = : 0.77
1
(1+√1-x)²¹
at x
J
x2
7.
8. y = 5²x+1, at x = 0.1
9. y = e√x, at x = e
J
f(x) = √√1+ √1 − x, at x =
10. y = sin (lnx²), at x =
π
-
4
114

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