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- A load has a leading power factor. a) Is it a capacitive or inductive load? b) Is the reactive power positive or negative? c) Repeat for a load with lagging power factorUse the information below to answer questions 24 und 25. The voltage across and the current through a load are (10+ j5Y and (2-jiArespecively. 24. What is the reactive power in VArconsumed? D. 0 A. 15 C. 20 D. 25 25. What is the pawer factor of the load? A. 0.8 leading B. 0.8 Jagging. -D. 0.6 ligging C 0.6 leading1. A load of 50 ohms resistance and 0.4 H inductance are connected in series to 100 volts, 60 hz a-c source. What must be the value of the capacitance to be connected in parallel to the circuit to raise the power factor to 0.96 lagging. Draw the circuit diagram.
- Which cannot be said since Z is an inductive load in the circuit given below? A) load voltage period is 0.02sec. B) Load voltage peak value is 311V. C) Load voltage frequency is 50Hz D) Load voltage average value is 220V.)Two complex loads Z1 and Z2 are connected in parallel and powered by a value voltage effective 7.2 kV and frequency 60 Hz. The first load has a power of 50 kVA and a factor of rear power of 0.9. The second charge has a power of 45 kW and a rear power factorof 0.91. Determine in steady state the kVAR power and the capacity required to correct the Total power factor to a value of 0.97 rear.Please read questions carefully i need power factor and Reactive power of load
- Calculate the value of capacitance in the following figure that must be connected in parallel with the load to correct the source power factor to 0.94 lagging. The frequency f = 60 HzThe circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three-phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and ITThe circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three- phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and IT RO- SO TO IR Is IT U₁-380 V CARGA 1 P₁ =950 W cos p1=0,5 ind. CARGA 2 P₂=1.140 W cos p₂=1 CARGA 3 P3=760 W cos p3=0,5 cap.
- 2. A voltage applied to a load is V=208420°V and current through load is I=10 &-10° A. Find the following [SO 1] o complex power consumed by load • Is the load inductive or capacitive? o the power factor of the load o the reactive power consumed or generated by the load. o Does the load consume or supply reactive power? 3. A single phase motor draws 20 kVA at 0.70 lagging power factor from a 120 V source. The PUD desires to improve the power factor to 0.9 lagging by connecting a shunt capacitor bank across the terminals of the motor. Determine the size of the capacitor bank in VARS. Calculate the following: [SO 1] a) What are the initial load current, real and reactive powers of the load? b) What are the real and reactive power after adding the capacitor bank? c) What is the kVAr rating of the capacitor bank? (3) d) What is the load current? di) How is the load current affected by the load reactive power?If a Load absorbs 20 kVA at a lagging power factor of 0.6. Then the complex power is: Select one: a. -12000 + j16000 VÀ b. None of these c. 12000 + j16000 VA d. 12000 - j16000 VAProblem 1 • A sinusoidal source with frequency of 60 Hz and rms-voltage of 100 V is connected to an RL load of 10 ohms and 100 uH. Find Power Factor From Calculation Find Power Factor From Plot L=10mH find power factor from calculation only