4) Use Routh's stabilitu criterion to determineroots with positivue reat parts thehowmonySallowing equationhoss’+ s'• 10s + 70 =010 s

According to the question we have to find the value Routh hurwitz.

Answered: 4) Use Rauth's s tability criterion to…

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter21: Resistive-capacitive Series Circuits

Section: Chapter Questions

Problem 6RQ: A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating...

See similar textbooks

Similar questions

Calibri (Body) -11 by AaBbCcDx AaBbCcD AaBbC AaBbCc AaB AaBbCc. mat Painter BIU 1Normal 1No Spaci. Heading 1 Heading 2 Title Subtitle Chang Styles d Font Paragraph Styles IMPEDANCE QUIZ # 2 1. What capacitance when connected in series with a 500Q resistor will limit the current drawn from a 48-mV 465-kHz source to 20µA? * a. 144pF b. 145pF c. 146pF d. 147pF MY ANSWER: c.146pF 2. What is the total impedance at 20kHz of a series circuit consisting of a 1.5mH inductance, a 100Q resistance, and a 0.08uF capacitance? * a. 1340 41.7 b. 1930 L-37.2" C. 920 290 d. 530 2-12.6°
convert Geolal pos to stecndred pos CA+B) (AiBoc) CA +c.
Solve for low fre quenuy response ond overatl voltage gam- 10uF 0.5 k ohms Rs JOKA SOKA 6.8K
ASAP please help me now I'll leave a like, thank you.
so then how is Rth 0.8695 kOhms in the original explanation?
From step1, how did you get that 50+(80*j60/80+j60) = 78.8+j38.4? also in step 2, how did you get that 5/(0.0125-0.0167) = 143.63 + j191.89?
In the given circuit, a step down transformer with an RMS voltage as 110V /11-0-11 V is used with RL = 1 KO. Assume diode as Germanium and the input frequency is F= 50HZ. D, CT Vin RL D2 1- Name the given circuit. 2- Find The PIV. 3- Find Current trough load resistance. 4- Draw the Input and Output wave forms. all
Adpole having anomentp=3-5ŷ +lont nc m is located at Q(ir3)-4jinfveespa.ce Find uet pase)
the shunt capacitance is a capacitor O a. Between a phase and the ground O b. between phases and a phase to ground c. none of the answers O d. Between phases
A clipper is a device that removes either the positive half (top half) or negative half (bottom half), or both positive and negative halves of the input AC signal. In other words, a clipper is a device that limits the positive amplitude or negative amplitude or both positive and negative amplitudes of the input AC signal. In some cases, a clipper removes a small portion of the positive half cycle or negative half cycle or both positive and negative half cycles. In the below circuit diagram, the positive half cycles are removed by using the series positive clipper. QUESTION: In your own opinion. Why do we need to clip a certain amount of voltage in positive or negative or on both sides? What is the benefit of that in our devices or circuits in doing such thing?
What's the rise time for this system with its closed-loop poles as shown? 14 -6 -4 12 -j6 Select one: a. 0.607 sec b. 3.14 sec C. 1.80 sec d. 0.254 seC e. 0.554 sec
Solve thisthe topic is about : DELTA – WYE AND WYE –DELTA TRANSFORMATION

SEE MORE QUESTIONS

Recommended textbooks for you

Delmar's Standard Textbook Of Electricity

Electrical Engineering

ISBN:

9781337900348

Author:

Stephen L. Herman

Publisher:

Cengage Learning

Power System Analysis and Design (MindTap Course …

Electrical Engineering

ISBN:

9781305632134

Author:

J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:

Cengage Learning

Delmar's Standard Textbook Of Electricity

Electrical Engineering

ISBN:

9781337900348

Author:

Stephen L. Herman

Publisher:

Cengage Learning

Power System Analysis and Design (MindTap Course …

Electrical Engineering

ISBN:

9781305632134

Author:

J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS

4) Use Rauth's s tability criterion to determine how roots with positive real parts the many dollo wing equation hos : IS + S s'-s'• 10s + 70 =0