4-During the water of crystallization Mass of an empty crucible 40.60 g. experiment, the following data were collected for the hydrated salt use them to solve Q4 and Q5 42.02 g Mass of crucible + hydrated salt Mass of crucible + anhydrous salt 41.35 Molar mass of anhydrous salt 146.5g/mol 4- The % by mass of the water in the salt equals: B. 78.1 % C. 47.2 % D. 52.8% A.21.9 %

4-During the water of crystallization Mass of an empty crucible 40.60 g. experiment, the following data were collected for the hydrated salt use them to solve Q4 and Q5 42.02 g Mass of crucible + hydrated salt Mass of crucible + anhydrous salt 41.35 Molar mass of anhydrous salt 146.5g/mol 4- The % by mass of the water in the salt equals: B. 78.1 % C. 47.2 % D. 52.8% A.21.9 %

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter11: Solutions

Section: Chapter Questions

Problem 1P: A patient has a “cholesterol count” of 214. Like manyblood-chemistry measurements,this result is...

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A patient has a “cholesterol count” of 214. Like manyblood-chemistry measurements,this result is measured inunits of milligrams per deciliter (mgdL1). Determine the molar concentration of cholesterol inthis patient’s blood, taking the molar mass of cholesterolto be 386.64gmol1. Estimate the molality of cholesterol in the patient’sblood. If 214 is a typical cholesterol reading among men inthe United States, determine the volume of such bloodrequired to furnish 8.10 g of cholesterol.
6-21 Are mixtures of gases true solutions or heterogeneous mixtures? Explain.
Insulin is a hormone responsible for the regulation of glucose levels in the blood. An aqueous solution of insulin has an osmotic pressure of 2.5 mm Hg at 25C. It is prepared by dissolving 0.100 g of insulin in enough water to make 125 mL of solution. What is the molar mass of insulin?
ow do the properties of a nonhomogeneous (heterogeneous) mixture differ from those of a solution? Give two examples of nonhomogeneous mixtures.
100 90 80 NANO 70 60 CaCl 50 Pb(NO)2 40 KCI NaCi 30 20 KCIO 10 Ce,(SO.) 10 20 30 40 50 60 70 80 90 100 Temperature ('C) • If 25 g KNO.is dissolved in 100 g water at 10°C and the solution s cooled to 5°C, how much of the salt crystallizes out of the solution? Solubility (g of salt in 100 g H,O) KNO3 K,Cr,O,
Q3: A: What mass of AgNO3 is needed to convert 3.46g of Na2CO3 to Ag2CO3, and calculate the mass of Ag2CO3 will be formed? Discuss your results. 2A9NO3(aq) +Na¿CO3(aq) Ag2CO3() + 2NaNo3(ag) B: Calculate the Normality of solutions containing the following with discussing your results:- 1) 8 gm /L of Na2CO3 (when the CO32 reacts with two protons). 2) 9.5 gm /L of K2CR2O7 (the Cr is reduced to Cr3). Atomic weight (H= 1, C=12, 0=16, Cl= 35.5, Na=23, K=39, Pb=207.19, Cr=52, Ag= 107.8)
K o Mail - Thomps 2 8 https://app.101edu.co P Parchment Rel 3 80 F3 1 Write the balanced NET ionic equation for the reaction when Al(NO3)3 and Na3PO4 are mixed in aqueous solution. If no reaction occurs, simply write only NR. Be sure to include the proper phases for all species within the reaction. + $ 4 F4 04 03- 2 Reset TW6D2PHI.pdf 0₂ P 15 % 5 3 4 3 213202 F5 Unofficial Transcri Question 14 of 40 4 -> Al O < 6 A 5 6 7 5 = 0+ F6 UAFS Registra Graduation Applica 6 MacBook Air ²+ & 7 07 NR N 0 3+ 7 8 9 0 09 口。 F7 (s) (1) (g) (aq) 8 4+ •x H₂O 8 CMy.UAFS - Stu Na DII FB Delete 9 F9 M Inbox ( ☆ F1
03.) The compound sodium thiosu Hate pentahyclrate, NazS,0g- H20, s importont commercially to the photography business as" hypo," because it has the ability to dissolve unreated silver salts from photographč film during develepment. Soplum thiosulfat pentahydrate Con be produced" by boiling elemental sulfur . o0 aque ous hunbalarced) solution of sochum sulfite SpIsst NazSOzlagy+H20(1) >Naz Sz@:SH2015)
uniform. There are two components of a solution Druct laE onormmoo eT T91s alnemibnoo bool Jaovi noitensgeng A solute is the component being dissolved and is in lower or smaller amount.bns alleg A solvent on the other hand is the component that dissolves the solute and is the emoe higher or bigger amount. rted etew iw 1eritegot alool svongmi bne niole esihutalom an beeu cals e1s 8eulxim lo jol A bne Inepisleb 19bwog riiw bexim niemdr nothibnoo ritisert ens eeesoeib eiuo terlf eenioibeM INoo pniwollol orlt vitrieol noilosi onibiooos nsld arit no eman iert aw.bns xod adi ebiani esonstac Soluton The additive is dissolved and thoroughly mixed into the main component. Its main component is called solvent, the dissolved additive is called the solute.Water is considered as a universal solvent. Direction:Identify the Solute and Solvent for each type of solution .Write your answers in column A Solute and column B Solvent. Solution Solute Solvent booR. 1.Sugar and Vinegar Solution enimoo1a…
Although other solvents are available, dichloromethane(CH₂Cl₂) is still often used to “decaffeinate” drinks because thesolubility of caffeine in CH₂Cl₂ is 8.35 times that in water.(a) A 100.0-mL sample of cola containing 10.0 mg of caffeine is extracted with 60.0 mL of CH₂Cl₂. What mass of caffeine re-mains in the aqueous phase? (b) A second identical cola sampleis extracted with two successive 30.0-mL portions of CH₂Cl₂.What mass of caffeine remains in the aqueous phase after each extraction? (c) Which approach extracts more caffeine?
- 1 A certain liquid X has a normal freezing point of –1.00 °C and a freezing point depression constant K,=2.88 °C·kg•mol *. A solution is prepared by dissolving some zinc chloride (ZnCl,) in 350. g of X. This solution freezes at -2.1 °C. Calculate the mass of ZNC1, that was dissolved. Be sure your answer is rounded to the correct number of significiant digits. alo 18.2 g Ar х10
A commercial vinegar is analyzed for the percent acetic acid present. The data for the first trial is given below. Calculate the required quantities using the raw data below. Preparation of Vinegar Sample: • Mass of vinegar (g) = 3.06 Analysis of Vinegar Sample: • Buret reading, initial (mL) = 25.40 • Buret reading, final (mL) = 3.70 . Molar concentration of NaOH solution (mol/L) = 0.0940 Calculate the volume of NaOH used (mL). Number answer only, do not write units. Do NOT write answer in scientific notation.