3. What would be the approximate concentration of the oxalate ion (C₂04²) of a 0.020 M solution of oxalic acid? Ka₁ = 5.9 x 10-² Ka₂ = 6.4 x 10-5 a. 6.4 x 10-5 M O b. 5.9 x 10-² M c. 0.020 M d. 1.0 x 10-2 M

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Problem 3ALQ: You need to make 150.0 mL of a 0.10 M NaCI solution. You have solid NaCl, and your lab partner has a...
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3. What would be the approximate concentration of the oxalate ion (C₂04²)
of a 0.020 M solution of oxalic acid?
Ka₁ = 5.9 x 10-²
Ka₂ = 6.4 x 10-5
a. 6.4 x 10-5 M
b. 5.9 x 10-2 M
c. 0.020 M
O d. 1.0 x 10-² M
Transcribed Image Text:3. What would be the approximate concentration of the oxalate ion (C₂04²) of a 0.020 M solution of oxalic acid? Ka₁ = 5.9 x 10-² Ka₂ = 6.4 x 10-5 a. 6.4 x 10-5 M b. 5.9 x 10-2 M c. 0.020 M O d. 1.0 x 10-² M
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