solve very very fast in 15 min | I need a clear answer by hand, not by keyboard 3. The reaction: 12(g) + F2 (g) → 2 IF(g), Kc =1×106 at 2000k if the partial pressure of IF at equilibrium = 0.2atm, F₂= 4x10-3 atm. The partial pressure of I₂ is:a. 5x104b. 1×10-³c. 1x10-5d. none of them4. In case of anprocess, the temperature of the system increasesb. adiabatic compressionc. isothermal expansiona. adiabatic expansiond. isothermal compression5. A 25.0 gram sample of a compound contains 6.64 grams of potassium (K, at.wt. = 39.1), 8.84 grams of chromium(Cr, at.wt. = 52.0), and 9.52 grams of oxygen (O, at.wt. = 16.0). The empirical formula of this compound isa. K₂Cr₂O7b. K₂CRO4c. K3CrO3d. K7Cr₂0₂e. KCrO4

Answered: Image /qna-images/answer/6e04903b-5f2a-4e08-9ca8-3369dc1baa83.jpg

3. The reaction: 12(g) + F2 (g) → 2 IFg), Kc =1×106 at 2000k if the partial pressure of IF at equilibrium = 0.2 atm, F₂= 4x10-3 atm. The partial pressure of I₂ is: a. 5x104 b. 1×10-3 c. 1x10-5 d. none of them

3. The reaction: 12(g) + F2 (g) → 2 IFg), Kc =1×106 at 2000k if the partial pressure of IF at equilibrium = 0.2 atm, F₂= 4x10-3 atm. The partial pressure of I₂ is: a. 5x104 b. 1×10-3 c. 1x10-5 d. none of them

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 105QRT

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solve very very fast in 15 min | I need a clear answer by hand, not by keyboard

3. The reaction: 12(g) + F2 (g) → 2 IF(g), Kc =1×106 at 2000k if the partial pressure of IF at equilibrium = 0.2
atm, F₂= 4x10-3 atm. The partial pressure of I₂ is:
a. 5x104
b. 1×10-³
c. 1x10-5
d. none of them
4. In case of an
process, the temperature of the system increases
b. adiabatic compression
c. isothermal expansion
a. adiabatic expansion
d. isothermal compression
5. A 25.0 gram sample of a compound contains 6.64 grams of potassium (K, at.wt. = 39.1), 8.84 grams of chromium
(Cr, at.wt. = 52.0), and 9.52 grams of oxygen (O, at.wt. = 16.0). The empirical formula of this compound is
a. K₂Cr₂O7
b. K₂CRO4
c. K3CrO3
d. K7Cr₂0₂
e. KCrO4

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