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- 6)Rank the following compounds in order of increasing pKa values, and explain your choices in detail.A) Phenol Red is a weakly acidic dye which is yellow in the HA form and red in the A form. What concentration of Phenol Red is required to obtain an absorbance of 0.50 at 550 nm at pH 7.8? Note: ε550 of A = 2.5 x 104 M-1 cm-1; ε550 of HA = 0; pKa = 7.8. B) What would the absorbance of the solution in part (a) be if the pH was 8.8?1 (a) In the following reactions, CI (1) LIAIH, A (2) H20 MCPBA (i) Draw the structure of compounds A and B. (ii) For each reaction, explain the type of reaction involved. (iii) Explain the successful transformation of compound A using mass spectra. (b) Complete the following reactions by filling in missing reactants or product. (i) (1) O3 (2) CH;SCH3 (ii) он (CH3)3(COOH) D Ti(OCH(CH3)2l4 (-)-DET
- 08) The NMR spectra of the two isomeric compounds with formula C3H5ClO2 are shown in letters a and b. Low-field protons appearing in the NMR spectrum around 12.1 and 11.5 ppm, respectively, are shown highlighted. Draw the structures of the isomers.51. Which is NOT a valid resonance structure for the conjugate base of this molecule? (A) (C) S (A) OEt O :O: : OEt HBr ROOR OCH 3 (B) 52. What is the major product of this reaction sequence? O PPh3 (D) 11 Mg ether (B) de OEt :0 aom Сосно LOCH 3 53. Which reagent is necessary for this transformation? (D) H OEt H OEt CH31 PPh3 ACS 56.(a) Tsomane and Nyiko were given a task of synthesising methylenecyclohexane 2. After a brief discussion with each other, Tsomane proposed Method A to synthesise 2 from cyclohexanone 1 while Nyiko proposed Method B that started from hydroxymethylcyclohexane 3. Each student believed that their proposed method is better than the other. (Scheme below) Ph THF A Ph Ph B H₂SO4 100 °C 3 OH (iii) In analysing both these methods, are there other possible alkene products other than methylenecyclohexane 2? Use mechanistic details to support your answer.
- Determine product (A) of the reaction (1) NK + DMF CH2 – Br (A) (81%) (2) HO¯/H2O (Benzyl bromide) (a) Ph – NH2 (c) Ph – CH2 – NH – CO,H (b) Ph – CH2 – NH2 (d) Ph – CH, - NH – CHOCompounds A and B are isomers having the molecular formula C4H8O3. Identify A and B on the basis of their 1H NMR spectra.Compound A: δ 1.3 (3H, triplet); 3.6 (2H, quartet); 4.1 (2H, singlet); 11.1 (1H, broad singlet)Compound B: δ 2.6 (2H, triplet); 3.4 (3H, singlet); 3.7 (2H triplet); 11.3 (1H, broad singlet)The 1H and 13C NMR spectra of compound A, C8H9Br are shown below. Answer the following questions. 1(a) Degree of the unsaturation of this compound is = , 1(b) The derived unsaturation number indicates that compound has ............= 1(c) Two peaks in between 6.5 - 8.0 δ indicate that compound is= 1(d) According to the splitting pattern of the peak at 1.20 δ and 2.58 δ indicates that compound has a .................. group= 1(e) According to the 1H NMR spectrum the number of nonequivalent aromatic proton sets in the compound = 1(f) According to the 13C NMR, the number of nonequivalent carbons in the compound is = 1(g) According to your answer in Q 1(f) the compound has a plane of symmetry Yes or NO = 1(h) The IUAC name for this unknown compound isNOT TOO SURE ABOUT MY ANSWERS, PLEASE CORRECT ME IF I'M WRONG
- The structure of an ester could either be A or B: CH3 O O CH3 T || -C-OCH3 CH3-C CH3-C-O-C-CH3 CH3 CH3 A B Its ¹H NMR spectrum consists of two peaks at 80.9 and 83.6 (relative areas 3:1). Which compound is it? Describe the spectrum that would be expected if it had been the other ester.Deduce the identity of the following compound from the spectral data given. C8H10: 1H NMR, 6 1.20 (3H, triplet), 2.60 (2H, quartet), 7.12 (5H, singlet) (ppm); IR, 3050, 2970, 1600 cm-1; MS, m/z 913. Which anion is the weakest base? (A) (B) 4. For the structure shown below, which is the least acidic hydrogen? (В) (A) но- (D) -NH3* CO2H (C) 5. Which of the following compounds will be the most reactive toward nucleophilic attach? OCH3 (A) `CI (B) `NH2 (D) (C) 6. What is the product of following reaction sequence? Choose fro answers A, B, and C. NaOCH3 CH3I(Excess) ? Он B