3. Calculate the AH for the following reaction: B2H6 + 6 Cl2 → 2 BCI3 + 6 HCL Given the following information: BCI3 + 3 H20 → H3BO3 + 3 HCI AH = -113 kJ B2H6 + 6 H20 → 2 H3BO3 + 6 H2 AH = -494 kJ %3D 2 H2 + ½ Cl2 → HCI AH = -92 kJ %3D

World of Chemistry
7th Edition
ISBN:9780618562763
Author:Steven S. Zumdahl
Publisher:Steven S. Zumdahl
Chapter10: Energy
Section: Chapter Questions
Problem 47A
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Calculate delta H Thanks
3. Calculate the AH for the following reaction:
B2H6 + 6 Cl2 → 2 BCI3 + 6 HCL
Given the following information:
BCI3 +3 H20 → H3BO3 + 3 HCL
AH = -113 kJ
B2H6 + 6 H20 → 2 H3BO3 + 6 H2
AH = -494 kJ
2 H2 + 2 Cl2 → HCI
AH = -92 kJ
Transcribed Image Text:3. Calculate the AH for the following reaction: B2H6 + 6 Cl2 → 2 BCI3 + 6 HCL Given the following information: BCI3 +3 H20 → H3BO3 + 3 HCL AH = -113 kJ B2H6 + 6 H20 → 2 H3BO3 + 6 H2 AH = -494 kJ 2 H2 + 2 Cl2 → HCI AH = -92 kJ
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