3. Assume the following register mappings: a= $t0,b=$t1 Show 2 different implementations to execute the 1-way if. if (a < b + 3) a = a + 1 b=b+a
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- 8. Show the steps involved in the following MOV AL,6EH ; AL=6EH ; BH=1CH ; subtract BH from AL. Place result in AL. MOV BH,1CH SUB AL,BH Find out the contents of the flag register.|long arith(long x,long y,long z) { long t1=x+y; long t2=z+t1; long t3=x+4; |long t4=y*48; long t5=t3+t4; long rval=t2*t5; return rval ; } In what registers are the arguments x, y, and z passed? In what register is variable rval returned? How many registers are involved in the execution of all the ALU operations? How many bytes are allocated to the stack frame of function arith? Justify your answer. Annotate each line of the assembly code obtained from the compiler and include the screenshot.(Practice) State whether the following are valid function names and if so, whether they’re mnemonic names that convey some idea of the function’s purpose. If they are invalid names, state why. powerdensity m1234 newamp 1234 abcd total tangent absval computed b34a 34ab volts$ a2B3 while minVal sine $sine cosine speed netdistance sum return stack
- Microprocessor Fundamentals AVR please solution with explain 7) Write a program to do the following: 1- Make all pins of Port C to be Output pins. 2- Make all pins of Port D to be Input pins. 3- Make pin PB5 of Port B to be output pin using SBI or CBI. 4- Make pin PB6 of Port B to be input pin using SBI or CBI. 5- Output the value $25 to Port C. Q8) Write a Main Program to do the following (place it at address $0204): 1- Enable INTO interrupt and disable INT1 interrupt. 2- Make INTO ot be triggered by a rising edge. 3- Set the Global Interrupt Enable flag.The ADD and SUB operators affect all the status flags according to the result of the operation. Give the outputs of the following sequential operations in assembly language and determine whether overflow flag (OF) or carry flag (CF) will be signaled. al, al, al, al, al, al, mox OFFh add 1 mox 7Fh add 1 80h mox add 80hA, B and C are in XO, X1, X2; and A=6, B=3, C=9. ZERO is a special register holding the value of O. What is the final value in X2 after executing the following code? SUB X4, XO, X1 BLE X4, ZERO Else Then: ADD X2, X2, XO Jump Exit SUB X2, X2, XO MUL X2, X2, 2 Else: Exit:
- 8. Write the contents of AL and BL register after execution of the program MOV AL, FFh MOV BL, AL TEST AL, BLH SUB BL,0FH HLT AL= BL=We can change order of operation precedence usingTopic: Assembly Language Write a program called bit_check.asm that jumps to a label if either bit 4, 5, or 6 is set in the BL register. If these bits are set the program should print "Bits 4, 5, or 6 are set." followed by a new line character. If they are not set, jump to a label to print "Bits 4, 5, and 6 are not set." followed by a new line character. There should be 4 tests, test with each bit position set and with none of them set. Use the print_string procedure to print your output. Remember, you can jump to the exit label from anywhere in your program.
- The following instruction is used for: GPIO PORTA_DIR_R 6= -0x20; Select one: a. direction PAS output O b. direction PFS input c. direction PA4 input d. direction PAS input e. direction PFS outputProgramming Project: For Loops Write an Assembly Language Program that produces the Times Table for a specific integer value between 1 to 12. NOTE: You choose and hard code only one value (i.e. 7) and produce the times table for that value. Also note that since you are using registers and memory locations make sure that at each step you screen shot each result for each part of the Times Table. For example 7 x 12 = 84 but in Hexadecimal the value is 54. Sample code in C #include void main() ( int i, j; printf("Enter an integer: "); scanf("%d", &i); printf("Times %d Table\n", i). for(j = 0; j<= 12; j =j+1) { printf("%d x %d = %d\n", j, 1. j'i); } printf("\n");Write the VHDL code for the following state diagram. No need to include user constraint file. B' B' B Reset в B' Initial On Off count := 0 count := count +1 output := count/2 output := 0