3. Assume a 2-way set associative cache with a 8 2-byte blocks. For each reference, list the binary address, the tag, the index, and if the reference is a hit or a miss, assuming the cache is initially empty.
Q: Question Consider a 4 way set associative cache made up of 64 bit words. The number of words per…
A: GIVEN:
Q: Make the difference between a cache that is directly mapped and one that is totally associative.
A: The answer is given in the below step
Q: Suppose that the following direct mapped cache is given, where it is composed of 8 blocks of 4 word…
A: Block size = 4 words So block offset = 2 bits Total # of block inside cache = 8 So index bits = 3…
Q: a direct-mapped cache with 128 blocks. The block size is 32 bytes.Find the number of tag bits, index…
A: The ask is to find the number of tag bits, index bits, and offset bits in a 32-bit address. Find the…
Q: The following is a list of 32-bit memory address references, given as word addresses of 8-bit each.…
A: The solution in step 2:
Q: For a direct-mapped cache design with a 32-bit address, the following bits of the address are used…
A: Directly Mapped : Index Bits = 4 Offset : 6 Total bits : 32
Q: For a direct mapped cache with 6-word a block, 33-bit address and 18-bits index , calculate the…
A: Let’s see some points on Direct Mapping.Direct mapping is that the simplest technique which maps the…
Q: For the hexadecimal main memory addresses 111111, 666666, BBBBBB, show the following information, in…
A: we have: The hexadecimal main memory addresses 111111, 666666, BBBBBB,
Q: Given a 2-way set associative cache of 64 Bytes, with block size = 8 bytes, LRU replacement policy,…
A: Solution: Given, Over here given cache is 2 way set associative cache, total size of 64 Bytes and…
Q: For a direct-mapped cache design with a 32-bit address, the following bits of the address are used…
A: Word size is 32 bits = 4 bytes Assume byte-addressable memory. As the offset field is 5…
Q: According to the Direct-Mapped cache, the format of the address is given below, Suppose the main…
A: Given: We are given a direct-mapped cache organization. The address format is also given where Tag…
Q: For a physically Indexed L1D cache, what is the average read latency if TLB hit rate is 99.5% and…
A: It is defined as a high-speed memory, which is small in size but faster than the main memory (RAM).…
Q: Explain why it is difficult to develop a suitable cache replacement technique for all address…
A: Answer: Cache algorithms (also known as cache replacement algorithms or cache replacement policies)…
Q: Consider a set-associative cache of size 2 KB (1 KB=210 bytes) with cache block size of 64 bytes.…
A: The calculation briefed below with given data
Q: We are given a list of 64-bit memory address references, given as word addresses. Ox03, Oxb4, Ox2b,…
A:
Q: For a direct-mapped cache design with a 64-bit address, the following bits of the address are used…
A:
Q: Consider a 4-way set ansociative cache made up of 64-bit words. The number of words per line is 8…
A: Cache memory is the faster then RAM. Its size is small as compared to RAM.
Q: Consider a 64K L2 memory and a 4K L1 direct mapped cache with block sizes of 512 values. a. How…
A: L1 cache size = 4 KB = 212 B L2 cache size = 64 KB = 216 B block size = 512 B a) no. of blocks in…
Q: If there is a 64K cache with a block size of Ik, what is the number of bits in the index field of…
A:
Q: What exactly is a fully associative cache, and how does it work in practise?
A: The fully associative cache The cache is built as a single cache set containing numerous cache…
Q: Given the following sequence of address references in decimal: 20000, 20004, 20008, 20016, 24108,…
A: Cache HitA cache hit is a state in which the requested data is located in the cache memory for…
Q: Consider a machine with Byte Addressable main Memory of 4 GB ivided in to blocks of size 32 bytes.…
A: Here in this question we have given main memory= 4 GB Block size = 32B Tag = 18 bit Find - no of…
Q: main memory address FEDCBAH, show the following information in hexadecimal format:
A: The given hexadecimal address is FEDCBA The binary equivalent of the given hexadecimal number is…
Q: Assume there are three small caches, each consisting of four one word blocks. One cache is fully…
A: Assume there are three small caches, each consisting of four one word blocks. One cache isfully…
Q: What are some of the reasons why it is difficult to create a cache replacement policy that is…
A: Optimal Algorithm says supplant page that will not be used for longest period oftime.
Q: Explain why it is difficult to create an optimum cache replacement policy for all address sequences.
A: Introduction Explain why it is difficult to create an optimum cache replacement policy for all…
Q: 2. Assume a direct-mapped cache with 4 4-byte blocks. For each reference, list the binary address,…
A: Given: Note that you will need to convert them to binary: 3, 180, 43, 2, 191, 88, 190, 14, 181, 44,…
Q: A direct-mapped cache is designed to store four words per cache line. It has 256 cache lines.…
A: Block size = 4 words = 4*4B = 16B So block offset bits is log 16=4 bits
Q: Using the references from Exercise 5.2, show the final cache contents for a fully associative cache…
A: Given: The cache is a fully-associative cache. The cache has one-word block. Total size is “8” word…
Q: Q20: Assuming an initially empty 2-way set associative cache with a block size of 2 words and a…
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Q: For a direct-mapped cache with 32KB of data and 8-word blocks. 1. What's the size of tag field if…
A: 1. Block size = 8 words= 8*4=32B Therefore block offset bits = log 32 = 5 bits Total number of block…
Q: pletely as
A: Each block in main memory can be placed anywhere in the cache in a full associative cache…
Q: A virtual address of 32 bits is passed on to the TLB. If the number of entries (number of cache…
A: Please upvote. I am providing you the correct answer below. please. For solving this question we…
Q: Suppose a computer using direct mapped cache has 232 words of main memory, and a cache of 1024…
A: Given: Suppose a computer using a direct-mapped cache has 232 words of main memory and a cache of…
Q: There is a cache with 8 blocks, find the number of misses for each cache organization…
A: Given: There is a cache with 8 blocks, find the number of misses for each cache organization…
Q: Determine which bits in a 32-bit address are used for selecting the byte (B), selecting the word…
A: 4-way set-associative cache Cache line size- 64 bytes Number of cache lines - 4096 Number of sets =…
Q: What are the three fields in a set-associative cache address, and how are they used to access a…
A: Set associative cache address Set associative cache mapping is used for having two or more words…
Q: te offset of 2 in an address means that each set in a multiway set associative (or in the directly…
A: It is defined as a small-sized type of volatile computer memory that provides high-speed data access…
Q: Determine which bits in a 32-bit address are used for selecting the byte (B), selecting the word…
A: In the fully associative cache, there are only tag bits and byte offset bits. No indexing is done in…
Q: Consider a 64K L2 memory and a 4K L1 2-way associative cache with block sizes of 512. a. How many…
A: Given, size of L2 = 64K and size of L1 = 4K associativity = 4 - way and , block size = 512
Q: .2: Below is a list of 32-bit memory address references, given as word addresses. 3, 180, 43, 2,…
A: Given addresses are 3, 180, 43, 2. 191, 88, 190, 14, 181, 44, 186, 253. Size of the block = 1 word…
Q: Hi, For this question I was curious about the Hit/Miss. There are people saying that the third hit…
A: According to given table,each of the access will be discussed now step by step. Access : 1 For index…
Q: Describe why it is difficult to create an appropriate cache replacement strategy for all address…
A: Given: Explain why it's tough to come up with a cache replacement approach that works for all…
Q: Exactly which data fields are accessible to the supplied log processing function? The following code…
A: INTRODUCTION: DATA FIELD: A data field is a storage space for a specific type of data that, when…
Q: Assume there are three small caches, each consisting of four one-word blocks. One cache is fully…
A: Solution Fully Associated 4- caches block number or miss = 3
Q: 2. 3) Using the series of references given in the following table, show the hits and misses and…
A: In case of set associative cache we use relation p % s = i to map the memory block address to the…
Q: Below is a list of 32-bit memory address references, given as word addresses. 3, 180, 43, 2, 191,…
A:
Q: Consider a 2-block fully associative cache. The following blocks from main memory are accessed which…
A: Given, The cache is a 2-block fully associative cache. Number of blocks in the cache = 2 The blocks…
Q: Given a 2-way set-associative cache with 2 entries (sets) and 1 byte block size (no offset), what is…
A:
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- adres veri 01h 5x9 02h 5x8 8715683 b190100564 7156 08h 6715988 5x2 bis010054 71 09h 5x1 Write the asm code that will create the address and contents given in the table. (It is mandatory to use loop and indirect addressing.) b10100564 159 190100564-7I5The Basic Computer stored a program in their memory unit as shown below. Fill Out the following table with the content of the registers (AC, PC, IR) after each instruction is executed. Note: all numbers are in the hexadecimal. 000 CLA 001 Add 016 AC PC 010 Bun 014 21 013 Halt 014 And 017 015 Bun 013 016 A001 017 DFFFAssume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Page Table Physical Memory Physical Address (starting) Oxppppdddd Page Frame Frame Size (hex) Size (dec) Ox10000 Ox10000 2 Охс000 65536 PPpp: page number dddd: page offset 1 1 Оxd000 65536 3 2 Охе000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for 0x00011119 What is the physical address for 0x00000001 What is the logical address for Oxd0000001 ? What is the logical address for Oxc0000002 ?
- The memory location at address 00002001 contains the memory variable in binary form. What is the data memory variable in hexadecimal form? MEMORY 1110 1011 00002001 1110 1010 00002000 1110 1001 00001999 1110 1000 00001998 1110 0111 00001997 1110 0110 00001996 DATA ADDRESS The data memory variable in hexadecimal form is E7. a. b. The data memory variable in hexadecimal form is EA. The data memory variable in hexadecimal form is EB. C. The data memory variable in hexadecimal form is E9. Od.Determine the machine code of the given instructions. Include operand or address size prefix. For the opcode,d,w, mod, reg, R/M use binary. For displacement and prefix, use hexadecimal. Write the displacement right after the modregR/M. The leftmost column will the If the given values are fewer than needed in the problem, add zero/es to the most significant place.Use single space in between bytes. Parenthesis is considered as bracket. e.g. Given: MOV (SI+12),DI Answer: 1001001 01111100 12 MOV (DI+9DFH), DEFAHVariable x has 4-byte representation 0x01234567 Address given by &x is 0x100 If the machine uses little endian byte ordering which of the following table presents variable in machine memory Select one: a. Ox100 :67 Ox001: 45 Ox102: 23 Ox103: 01 b. 0x100 : 76 Ox001: 54 Ox102: 32 Ox103: 10 O c. Ox100:01 Ox001: 23 Ox102: 45 Ox103: 67 d. 0x100 : 10 Ox001: 32 Ox102: 54 Ox103: 76 Clear my choice
- Determine the machine code of the given instructions. Include operand or address size prefix. For the opcode,d,w, mod, reg, R/M use binary. For displacement and prefix, use hexadecimal. Write the displacement right after the modregR/M. The leftmost column will the If the given values are fewer than needed in the problem, add zero/es to the most significant place.Use single space in between bytes. Parenthesis is considered as bracket. e.g. Given: MOV (SI+12),DI Answer: 1001001 01111100 12 MOV BX, (EDX+(EDI*4)) Blank 1Determine the machine code of the given instructions. Include operand or address size prefix. For the opcode,d,w, mod, reg, R/M use binary. For displacement and prefix, use hexadecimal. Write the displacement right after the modregR/M. The leftmost column will the If the given values are fewer than needed in the problem, add zero/es to the most significant place.Use single space in between bytes. Parenthesis is considered as bracket. e.g. Given: MOV (SI+12),DI Answer: 1001001 01111100 12 MOV DX, (BP+DI) Blank 1Variable x has 4-byte representation 0x01234567 Address given by &x is 0x100 If the machine uses Big endian byte ordering which of the following table presents variable in machine memory Select one: a. 0x100 : 100x001: 320x102: 540x103: 76 b. 0x100 : 670x001: 450x102: 230x103: 01 c. 0x100 : 760x001: 540x102: 320x103: 10 d. 0x100 : 010x001: 230x102: 450x103: 67
- Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Physical Memory Physical Address (starting) Page Table Oxppppdddd Page | Frame Frame Size (hex) Size (dec) Ox10000 Ox10000 2 Охс000 65536 pppp: page number dddd: page offset 1 1 Oxd000 65536 2 2 Oxe000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for 0x0000ee00 ? What is the physical address for Ox00020001 ? What is the logical address for Oxe0001234 ? What is the logical address for Oxc0004268 ?Below is a list of 64-bit memory address references given as word address. Ox03, Oxb4, Ox2b, Ox01, Oxb7, Ox58, Oxbe, Ox02, Oxb5, Ox2e, Oxb6, Ox5b 0000 4 0100 8 1000 1100 1 0001 5 0101 9 1001 d 1101 2 0010 6 0110 a 1010 e 1110 3 0011 7 0111 b 1011 f 1111 Given a direct-mapped cache with 16 word blocks, what is the hit ratio? O 0.5 O 1 O 0.75 O 0.25Variable x has 4-byte representation 0x01234567 Address given by &x is 0x100 If the machine uses little endian byte ordering which of the following table presents variable in machine memory Select one: O a. Ox100 : 10 Ox001: 32 Ox102: 54 Ox103: 76 O b. Ox100: 67 Ox001: 45 Ox102: 23 Ox103: 01 O c. Ox100:01 Ox001: 23 0x102: 45 0x103: 67 O d. 0x100:76 Ox001: 54 Ox102: 32 0x103: 10