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3.
a. Briefly explain why internal standardization method is useful in
b. Why does a response factor of an instrument’s detector need to be
calculated?
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- Mass spectrometry is an extremely versatile detection system for GC. However, interfacing an HPLC system to a mass spectrometer is a much more difficult task. Describe the major reasons why it is more difficult to combine HPLC with mass spectrometry than it is to combine GC with mass spectrometry.Based upon the following calibration plot, what appears to be the analytically useful linear range of this metho 4000 Detector Signal (mv) 3500 3000 2500 2000 1500 1000 500 OLO.D.-> 50 mM LO.D. 100 mM OLO.D.-250 mM 50 100 mM-> 250 mM and beyond 100 150 Concentration (mm) 200 250Instrumental studies involve the calculation of the instruments' limit of detection (LOD) in addition to the calibration curve. a. What exactly is LOD? b. Why is it necessary to determine it? c. Hpw is it determined?
- Question 7 What variations are tolerated by an analytical method is described by the method's Select one: O a. Intra-assay precision O b. Limit of quantitation O c. Instrument precision O d. Linearity е. Robustness Checkwhat is the difference of spectrophotometer with ATR (attenuated total reflectance) and one without it. What are the advantages of one over the other?Which part of the instrument perform the given function introduction of a micro amount of sample converts sample components into gaseous ions orts the ions according to m/z converts m/z values to electrical signals converts signal/results into a mass spectrum A. mass analyzer B. Vacuum system C. Ion source D. Processor E. inlet system F. detectors
- River water analysis of mercury (Hg) yields a spectrophotometric sample signal of 0.712 for a 5.00 mL sample. A 5.OuL spike of 1560 ppb Hg standard produced a signal of 1546. What is the concentration of Hg in the original river water sample? What is the concentration of Hg in the original river water sample? A. 1.109 ppb B. 1.330 ppb C. 1.771 ppb D. 1.546 ppbQ5. Two methods were used to measure fluorescence lifetime of a dye. The average result for Method 1 is = 1.382 ns with a standard deviation of s1 = 0.039 and n1= 7. The average result for Method 2 is = 1.346 ns with a standard deviation of s2 = 0.015 and n2= 5. Is there a difference between the two methods at the 95% confidence level using F test?12. This detector is not used in HPLC: a) ECD b) MS c) Fluorescence d) RI
- (2) A CHEM 215 student performed 5 measurements of the wt% of SO4²- of a solid power sample. The results are 8.75%, 8.85%, 8.89%, 8.71%, 8.64%. The standard deviation is 0.10%. What is the confidence interval for this student's experiment at 95% confidence level. The t values for 95% confidence for degree of freedom from 1 to 5 are 12.71, 4.303, 3.182, 2.776, 2.571, respectively. Show your work!Is standardization against primary standard required for controlled potential coulometry ?If the peak width w of both Peak 1 and Peak 2 fro eon 1g is 0.5 minutes, what is the resolution factor between the two peaks? 1.13 Selectivity is Peak 1 (6.0 min, Peak 2 w=0.5 (6.8 min, w=0.5 25 min) min) 20 15 Hold up peak (1.8 min) 10 0. 0. 4. 8. time (minutes) 2. 5. Signal