2NF3(g)-> N2(g) + 3F2(g) When 3.15 mol of NF3 is placed in a 3.00-L container and allowed to come to equilibrium at 900 K, the mixture is found to contain 0.0563 mol of N2. What is the value of K, at this temperature? (R = 0.0821 L-atm mol¹K). (Hint: Solve for Kc first, then calculate Kp) 4.43 x 10-7 1.8 x 10-2 1.11 x 10-5 1.91 x 10-3 1.07 x 10-5

2NF3(g)-> N2(g) + 3F2(g) When 3.15 mol of NF3 is placed in a 3.00-L container and allowed to come to equilibrium at 900 K, the mixture is found to contain 0.0563 mol of N2. What is the value of K, at this temperature? (R = 0.0821 L-atm mol¹K). (Hint: Solve for Kc first, then calculate Kp) 4.43 x 10-7 1.8 x 10-2 1.11 x 10-5 1.91 x 10-3 1.07 x 10-5

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 9QRT

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