28. Calculate the velocity of an enzyme-catalyzed reaction A+B P+Q at [A]=2x 10 M and [B]= 6.7x 10 M. Assumethat A and B add randomly to the enzyme and(a) a =1 (the binding of one substrate has noeffect on the binding of the other), (b) a 0.1(the binding of one substrate decreases the%3D dissociation constant for the other by a factorof 10). Preliminary experiments establishedthat KA 2.2 × 10 M, K 1.9x 10* M, andV= 72.7 nnoles x liter x min.Vmax

Solutions- Data given- [A] = 2.0 x10-3 M [B] = 6.7 x 10-3 M KA = 2.2 x 10-4 M KB = 1.9 x 10-5 M and…

28. Calculate the velocity of an enzyme- catalyzed reaction A+B P+Q at [A]= ex 10 M and [B]= 6.7x 10 M. Assume chat A and B add randomly to the enzyme and a) a 1 (the binding of one substrate has no effect on the binding of the other), (b) a =0.1 Cthe binding of one substrate decreases the %3D

28. Calculate the velocity of an enzyme- catalyzed reaction A+B P+Q at [A]= ex 10 M and [B]= 6.7x 10 M. Assume chat A and B add randomly to the enzyme and a) a 1 (the binding of one substrate has no effect on the binding of the other), (b) a =0.1 Cthe binding of one substrate decreases the %3D

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter11: Chemical Kinetics: Rates Of Reactions

Section: Chapter Questions

Problem 81QRT

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Question

28. Calculate the velocity of an enzyme-
catalyzed reaction A+B P+Q at [A]=
2x 10 M and [B]= 6.7x 10 M. Assume
that A and B add randomly to the enzyme and
(a) a =1 (the binding of one substrate has no
effect on the binding of the other), (b) a 0.1
(the binding of one substrate decreases the
%3D

dissociation constant for the other by a factor
of 10). Preliminary experiments established
that KA 2.2 × 10 M, K 1.9x 10* M, and
V= 72.7 nnoles x liter x min.
Vmax

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