(25) The position vector of an object of mass 0.50 kg subject to a constant force isgiven byr = (at²+bt) + (ct2+dt)j + (et2+ft) k, where a = 2.0 m/s², b = 3.0 m/s, c= 2.5 m/s2, d = -2.0 m/s, e = 1.0 m/s2, and f = 4.0 m/s. What is the angularmomentum of the object about the origin at t = 2.0 s? 12)A) (241-122-89 k) kg.m²/sk) kg.m²/sB) (25+14+20C) (25-14+20 k) kg.m²/sD) (-24 + 10+ 23 k) kg.m²/sE) (241 + 122+23 k) kg.m²/s

The mass of the given object, m=0.50 kg The position vector, r→=(at2+bt)i^+(ct2+dt)j^+(et2+ft)k^ The…

(25) The position vector of an object of mass 0.50 kg subject to a constant force is given by r = (at²+bt)i + (ct²+dt) + (et²+ft) k, where a = 2.0 m/s², b = 3.0 m/s, c = 2.5 m/s², d = -2.0 m/s, e = 1.0 m/s2, and f = 4.0 m/s. What is the angular momentum of the object about the origin at t = 2.0 s? 12) A) (241-122-89 k) kg-m²/s k) kg.m²/s B) (25+14+20 C) (25-14+20 k) kg-m²/s D) (-241 +10+23 k) kg-m²/s E) (24 + 122 +23 k) kg-m²/s

(25) The position vector of an object of mass 0.50 kg subject to a constant force is given by r = (at²+bt)i + (ct²+dt) + (et²+ft) k, where a = 2.0 m/s², b = 3.0 m/s, c = 2.5 m/s², d = -2.0 m/s, e = 1.0 m/s2, and f = 4.0 m/s. What is the angular momentum of the object about the origin at t = 2.0 s? 12) A) (241-122-89 k) kg-m²/s k) kg.m²/s B) (25+14+20 C) (25-14+20 k) kg-m²/s D) (-241 +10+23 k) kg-m²/s E) (24 + 122 +23 k) kg-m²/s

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 61P

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