24. From the following series of reactions find the free energy of formation of N;0.(g) at 25°C: 1 5 N:(g) +0:(g) = NO(g) AF2,8°K = 20,720 cal %3D 2 1 NO(g) +0:(g) NO:(g) AF = -8330 cal %3D 2 298°K 2 NO:(g) N0,(g) AF. 298°K -1380 cal

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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24. From the following series of reactions find the free energy of formation of
N;0,(g) at 25°C:
1
N:(g) + 0:(g) = NO(g)
AF9°K = 20,720 cal
NO(g) +02(g) = NO:(g)
2
AF298°K
-8330 cal
2 NO:(g)
N,0.(g)
AF
-1380 cal
%3D
298°K
Transcribed Image Text:24. From the following series of reactions find the free energy of formation of N;0,(g) at 25°C: 1 N:(g) + 0:(g) = NO(g) AF9°K = 20,720 cal NO(g) +02(g) = NO:(g) 2 AF298°K -8330 cal 2 NO:(g) N,0.(g) AF -1380 cal %3D 298°K
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