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- i li. In. O MMecnaniCS / مطلوب Untitled Section F1 F2 a F3 B. d F4 F5 Consider the following values: - a - 25 m; b - 5 m; a - 25 m; d - 5 m; F1 = 6 KN; F2 = 7 kN; F3 = 8 KN; F4 = 9 kN; F5 = 10 KN; a = 60°, 0 = 45°, B== 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 15.8 kN.m b) 74 kN.m c) 88 kN.m d) 59 kN.m e) 241 kN.m 0- 47 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 218.8 kN.m b) – 117.8 kN.m c) - 131.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) - 224.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 186.7 kN.m b) - 143.6 kN.m c) 114.6 kN.m d) - 217.9 kN.m e) 224.1 KN.m ) - 135.3 KN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 217.8 kN.m b) – 139.5 kN.m c) 111.9 kN.m d) 206.9 kN.m e) - 127.1 kN.m f) 99.1 kN.m Activate 5] What is the moment of the force F2 about point E? Go to Setting f) 321.3 kN.m a) 121.7 kN.m…plz provide answer for part c ques4Calculate the total moment of the system about point A, when P1 = 8 kN, P2 = 10 kN and 0 = 45°. %3D %3D 25 kN.m 1.5 m A –1.5 m- P2 →1.5 m- Select one: a. 23.21 kN.m (CCW) b. 48.21 kN.m (CW) c. 23.21 kN.m (CW) d. 48.21 kN.m (CCW)
- Define the term resultant forceThe force in the rope if F= 500 N. The dimensions of the beam are: AC = 2 m, AD= 3 m, DB= 2.5 m, h= 1 m and r= 0.3 m. F Ac PENDIDIK C AD DB Which side is the easiest to use to solve for the internal forces at C. O Left side, less forces. O Right side, less forces. Either sides have the same number of forces. BProblem 3. What is the moment of the 1.4 kN force along the direction of the 1.0 kN force? Express your answer as a magnitude and sketch the direction of rotation about the axis defined by the 1.0 kN force TIGBAO TK 1.0KN X 539 indi 21 150 mm 195 mm 2 4 160 mm 21% ARD 19TO 1.4 kN MEBIRT 0 DAW ITOM 00 1400
- What is the equivalent resultant force and specify its location, measured from point 0 Choices: FR= 12.5 kN, d= 1.54 m FR= 13.5 kN, d= 1.44 m FR= 12.5 kN, d= 1.64 m FR= 13.5 kN, d= 1.54 m1. force in each member. Compute the 2000 lb 3000 b 0° 60° A REH REN C 10' 10' RA 4000 1b REVQ5/A) From the figure below, determine the reaction force at pin C. A 000 0.6 m 10 kN 0.6 m 0.8 m 60° 0.4 m 6 kN OB
- QI5: Delermhe The resultant o. The forces shoan in figure () 4 KN 6.A 48KN CAKN 2 KN 54 KN Fy-(15)A truss is facing a two-force member and both of them are in the opposite directions, and the truss is in equilibrium. And both of them are coming to each other. The forces are called Select one: O a. Tensile Forces O b. Compressive forces O c Parallel and collinear forces with same direction of heading O d. The rotational forces Next page est-3 Jump to...Situation 4 The truee ia londed se ehown. 60 kN 120 kN 120 kN 120 kN 3m 3m 6m 3m Cnccse the magnitude (kN) ana type (tenaion or ocmpression) cf the foroe in member FE NOTE: Alweye ohocse two (2) anawere but if the member ia zeroforoe member ohoose one (1) anawer only. Seleot the correct reoponoe(o): Teneion 160 100 O 63.25 Compreseion 180 260 60 O 7211 50 56.06 O O O O O O O O