2. Suppose we want to compute the arclength of y = ln x from x = 1 to x = 3. (a) Write out the integral corresponding to the arclength. Don't try to solve it (it is very difficult to do using the FTC). (b) Write the values of the integrand (function inside the integral sign) for x = 1, 1.5, 2, 2.5, and x = 3 in a table, rounded off to the nearest thousandth. Then, approximate the arclength using the trapezoid rule and Simpson's rule using these five points.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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Section2.1: Tables And Trends
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Suppose we want to compute the arclength of y = ln x from x = 1 to x = 3.
(a) Write out the integral corresponding to the arclength. Don't try to solve it (it is very difficult to
do using the FTC).
(b) Write the values of the integrand (function inside the integral sign) for x = 1, 1.5, 2, 2.5, and x = 3
in a table, rounded off to the nearest thousandth. Then, approximate the arclength using the
trapezoid rule and Simpson's rule using these five points.
(For the sake of comparison, here is the exact answer, thanks to an integral calculator:)
In(V10 + 1) – In(v10 - 1) – In(v2+1) + In(v2 – 1) – 2/10 + 2
Approximation:
2.301987534577569
2.
Transcribed Image Text:Suppose we want to compute the arclength of y = ln x from x = 1 to x = 3. (a) Write out the integral corresponding to the arclength. Don't try to solve it (it is very difficult to do using the FTC). (b) Write the values of the integrand (function inside the integral sign) for x = 1, 1.5, 2, 2.5, and x = 3 in a table, rounded off to the nearest thousandth. Then, approximate the arclength using the trapezoid rule and Simpson's rule using these five points. (For the sake of comparison, here is the exact answer, thanks to an integral calculator:) In(V10 + 1) – In(v10 - 1) – In(v2+1) + In(v2 – 1) – 2/10 + 2 Approximation: 2.301987534577569 2.
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