2. solution of diprotic acid with molar mass 186.0 g/mol (Ka1= 7.1e-2 Ka2=6.1e-5) made by placing 35.90 g of the acid in 155 mL of solution. Solution titrated with 1.180 M KOH. What is pH at second equivalence point? 3. Solution made with 1.81 g Vitamin C (H2C6H6Ó6, Ka1=7.9e-5 Ka2=1.6e-12) dissolved in 201 mL of solution, titrated with 1.170 M KOH. Calculate pH at second halfway point

Chemistry: The Molecular Science
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Chapter15: Additional Aqueous Equilibria
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Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...
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2. solution of diprotic acid with molar mass 186.0 g/mol (Ka1= 7.1e-2 Ka2=6.1e-5)
made by placing 35.90 g of the acid in 155 mL of solution. Solution titrated with
1.180 M KOH. What is pH at second equivalence point?
3. Solution made with 1.81 g Vitamin C'(H2C6H6Ò6, Ka1=7.9e-5 Ka2=1.6e-12)
dissolved in 201 mL of solution, titrated with 1.170 M KOH. Calculate pH at second
halfway point
need help with both problems
Transcribed Image Text:2. solution of diprotic acid with molar mass 186.0 g/mol (Ka1= 7.1e-2 Ka2=6.1e-5) made by placing 35.90 g of the acid in 155 mL of solution. Solution titrated with 1.180 M KOH. What is pH at second equivalence point? 3. Solution made with 1.81 g Vitamin C'(H2C6H6Ò6, Ka1=7.9e-5 Ka2=1.6e-12) dissolved in 201 mL of solution, titrated with 1.170 M KOH. Calculate pH at second halfway point need help with both problems
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