2. Find the slope of the graph. Show your solution answer on the right column. Writethe appropriate unit of the final answer.Slopea. at t=0 h to t = 2 hb. at t= 2 h to t = 4 hc. at t= 4 h to t = 5 hd. at t= 5 h to t = 8 h3. What does the slope for a d-t graph represent?4. What does a positive slope show? A negative slope? A zero slope? Activity No. 1: Graphing Motion: Let's MoveTable 1Distance, d(km)Time, tI. Determining Slope on a Motion GraphA. Displacement-Time Graph1. Plot the given tabulated data (distance-time, d-t)from Table 1.(h)5011002100310041501006.5078.

Answered: Image /qna-images/answer/23ad15f9-0e15-4d40-9db7-136309da2c73.jpg

Answered: 2. Find the slope of the graph. Show…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Q1: 1 1 3 4 5 6 8 10 11 time (s) The above velocity- time graph for an object that moves as shown path. 1. Discuss the diagram. 2. Instantaneous acceleration after 1.5 second of staring. 3. The displacement during the first six seconds. 4. The acceleration last 2 seconds. velocity (m/s)
Fantastick. of 6) A Microsoft PowerPoint - chapter 2 x O Rotational system.pdf O Essay on Life in a Big City for Stu x 10 Advantages of Living A https://moodle1.du.edu.om/mod/quiz/attempt.php?attempt340840&cmid%3D2247468&page=D4 - Moodle English (en) - 01(1) 18 N-m-s/rad 1 N-m-s/rad T(1) 02(1) $ kg-m2 3 kg-m2 3 N-m/rad 9 N-m/rad (a) Figure P2.16a John Wiley & Sons, Inc. All rights reserved. The transfer function where the output Theta, is 0,(s) H(s) = T(s) s² +5s +1 s* +30s` +80s² +s +15 a. %3D S 0,(s) b. H(s)=- s´+5s +1 %3D 25s +30s +80s² +s+15 4. T(s) 0,(s) H(s)= - T(s) 5s² +9s +9 15s* +30s+95s² + s+ 27 c. 4. 5s +9s +9 0,(s) d. H(s)= T(s) 15s +32s +95s² +99s+ 27
a.mheducation.com/ext/map/index.html?_con%3Dcon&external_browser%3D08&launchUrl=https%253A%252... Check my NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. The bob of a simple pendulum of length /= 40 in. is released from rest when 0 = 5°. Assuming simple harmonic motion, determine the magnitudes of the velocity and acceleration of the bob after the pendulum has been in motion for 1.65 s. The magnitude of the velocity of the bob after the pendulum has been in motion for 1.65 s is 82699 ft/s. The magnitude of the acceleration of the bob after the pendulum has been in motion for 1.65 s is t/s2. Menu Tro Dicection In fuel
Here is a graph that shows a resulting position vs time graph of the astronaut when attached to a spring with a spring constant of k = 240 N/m. What is her speed when the spring is 0.5 meters away from its most "squished" position?f Position (meters) 6 5 3 cu 1 0 0 Astronaut Mass Determination Data 1 2 3 4 Time (sec) 5 6 7 8
B. C 15.0 m D 16.0r E 20.01 Which of the following charts TSTS shows a uniform velocity of a 4 5 Time (s) body in motion? length of tape/cm 3 of the body is 4. velocity/m 10 20 30 40 50 60 70 number of ticks gure 4 shows object. 1 length of tape/lam 8. 6. A veloc shown follow time/s 10 20 30 40 S0 60 70 number of ticks 12 14 motio length of tapelcm A T nce moved n it travels ity? 80 m 160 m 8. B. 6. D 10 20 30 40 5O 60 70 number of ticks
What mathematical relationship exists between the wave speed and the density of the medium, using the POWER trendline equation from the graph? Make your response specific (i.e., describe the full mathematical proportionality between the two variables) Feel free to use the table. Table: Frequency (Hz) Density (kg/m) Tension (N) Speed (cm/s) Wavelength (cm) 0.85 0.1 4.0 632.5 744.12 0.85 0.7 4.0 239.0 281.18 0.85 1.3 4.0 175.4 206.35 0.85 1.9 4.0 145.1 170.70
permanent-magnet (pm) genera x Bb Blackboard Learn L STAND-ALONE.mp4 - Google Dri x O Google Drive: ülwgjuó jc lis u O ME526-WindEnergy-L25-Shuja.p x O File | C:/Users/Administrator/Desktop/KFUPM%20Term%232/ME526/ME526-WindEnergy-L25-Shuja.pdf (D Page view A Read aloud T) Add text V Draw Y Highlight O Erase 17 of 26 Wind Farms Consider the arrangement of three wind turbines in the following schematic in which wind turbine C is in the wakes of turbines A and B. Given the following: - Uo = 12 m/s A -XẠC = 500 m -XBC = 200 m - z = 60 m - Zo = 0.3 m U. -r, = 20 m B - CT = 0.88 Compute the total velocity deficit, udef(C) and the velocity at wind turbine C, namely Vc. Activate Windows Go to Settings to activate Windows. Wind Farms (Example Answer) 5:43 PM A 4)) ENG 5/3/2022 I!
6. A ball is thrown straight up in the air at time t = 0. Its height y(t) is given by y(t) = vot - 791² (1) Calculate: (a) The time at which the ball hits the ground. First, make an estimate using a scaling analysis (the inputs are g and vo and the output is the time of landing. Think about their units and how you might construct the output using the inputs, just by matching units). Solve the problem exactly. Verify that the scaling analysis gives you (almost) the correct answer. (b) The times at which the ball reaches the height v/(4g). Use the quadratic formula. (c) The times at which the ball reaches the height v/(2g). You should find that both solutions are identical. What does this indicate physically? (d) The times at which the ball reaches the height v/g. What is the physical interpretation of your solutions? (e) Does your scaling analysis provide any insight into the answers for questions (a-e)? Discuss. (Hint: Observe how your answers depend on g and vo).
QI: 30 time (s) The above velocity- time graph for an object that moves as shown path. 1. Discuss the diagram. 2. Instantaneous acceleration after 1.5 second of staring. 3. The displacement during the first six seconds. 4. The acceleration last 2 seconds.
Using the following lines, let us create a virtual data concerning the joint torque (Nm) and angular velocity (RPM) of an imaginary actuator system: Kx = 29; Kn 200; dt 0.001; %sampling time 10; simulation time Ts ns Ts/dt +1; for i = 1:nS t(i) tau (i) = (i-1) *dt; time variable Kx*sin (2*pi*0.5*t (i)) + = 0.1*sin (2*pi*50*t (i)); dq (i) = Kn*cos (2*pi*0.5*t (i))*9.24; SOME CALCULATONS HERE end & THEN SOME OTHE CALCULATIONS HERE Calculate the average torque T_avg. Then referring the Harmonic Drive Catalogue, choose a gear model with a gear ratio of 1:30 in accordance with the T_avg value you calculated. Explain the rationale behind your choice.
... 6. Profile M Inbox ( Telegra Dropbe SIS -O Launch 29 (25) W Course Trading ONew Ta + zto.mheducation.com/ext/map/index.html?_con3Dcon&external_browser=D0&launchUrl=https%253A%252F%252Fnewconnect.mheducation.com%252F#/activity/question-gr... 42) 6 Saved Help Save & Exit Luqns Required informetion A cylindrical fuel rod (k = 30 W/m K) of 2 cm in diameter is encased in a concentric tube and cooled by water. The fuel rod generates heat uniformly at a rate of 100 MW/m3, and the average temperature of the cooling water is 80°C with a convection heat transfer coefficient of 2500 W/m2-K. The operating pressure of the cooling water is such that the surface temperature of the fuel rod must be kept below 200°C to avoid the cooling water from reaching the critical heat flux (CHF). The crițical heat flux is a thermal limit at whichr a boiling crisis can occur that cause overheating on the fuel rod surface and lead to damage. T(r.) é gen = 100 MW/m³ %3D Cooling water Fuel rod D=2 cm 2500 W/m2-K…
The graph to the right shows velocity vs. time for a cart on a track with a friction pad attached. The cart was launched from rest by a hoop spring. Use this graph to answer the following question: so long as the ramp is level, even with the friction pad NOT in contact with the track it is impossible to produce a region "b" that is flat (horizontal), i.e. that shows a constant velocity. This is because b V a of errors inherent to the motion detector the acceler tion gravity causes the cart to rate air currents in the room significantly affect the motion of the cart there is still a small amount of friction between the wheels of the cart and the track, and the axels of the cart with the body of the cart achieving constant velocity is not physically realistic under any circumstances

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