2. A parallel plate capacitor with a plate area of 0.13 square meters separated by 1 mm is charged to 9 Volts by a battery, which is then disconnected. The plate separation is then increased to 40 mm.A. Using the expression for the capacitance of a parallel plate capacitor, what do you expect the new potential difference across the plates to be after the increase?B. Suppose you measure the potential difference across the plates after the separation and find it to be 30 V (this should be very different from what you found in part A). This unexpected result can be explained by the effects of “stray capacitance” with nearby objects. Assuming that the stray capacitance can be modeled as a capacitor connected in parallel with the parallel plate capacitor, find the value of this stray capacitance.
2. A parallel plate capacitor with a plate area of 0.13 square meters separated by 1 mm is charged to 9 Volts by a battery, which is then disconnected. The plate separation is then increased to 40 mm.
A. Using the expression for the capacitance of a parallel plate capacitor, what do you expect the new potential difference across the plates to be after the increase?
B. Suppose you measure the potential difference across the plates after the separation and find it to be 30 V (this should be very different from what you found in part A). This unexpected result can be explained by the effects of “stray capacitance” with nearby objects. Assuming that the stray capacitance can be modeled as a capacitor connected in parallel with the parallel plate capacitor, find the value of this stray capacitance.
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