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2+ 2+ Based on the reaction, Sn + Cu²+ → Sn²+ + Cu* (in acidic medium) Calculate the following values: a. E cell [Identify which component is the cathode and anode, then look for their standard potential value and plug in the E^o]cell equation. A Table of Standard Electrode Potentials value can be found in the lecture slides; you may also search other additional or alternative preferences (make sure it is reliable). Some value may differ especially in the bird to fourth decimal places] b. AGⓇ [Use the standard cell potential value to solve the unknown.] c. K [Use the standard cell potential vale to solve the unknown.] d. E (when [Cu²+] = 0.0200 M, [Sn²+] = 0.0100 M, and [Cu*] = 0.0300 M) [Use the Nernst Equation to solve for the potential at nonstandard conditions. Identify which values to input in the Q.]

2+ 2+ Based on the reaction, Sn + Cu²+ → Sn²+ + Cu* (in acidic medium) Calculate the following values: a. E cell [Identify which component is the cathode and anode, then look for their standard potential value and plug in the E^o]cell equation. A Table of Standard Electrode Potentials value can be found in the lecture slides; you may also search other additional or alternative preferences (make sure it is reliable). Some value may differ especially in the bird to fourth decimal places] b. AGⓇ [Use the standard cell potential value to solve the unknown.] c. K [Use the standard cell potential vale to solve the unknown.] d. E (when [Cu²+] = 0.0200 M, [Sn²+] = 0.0100 M, and [Cu*] = 0.0300 M) [Use the Nernst Equation to solve for the potential at nonstandard conditions. Identify which values to input in the Q.]

Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 135CWP: Consider a galvanic cell based on the following half-reactions: a. What is the expected cell...
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[ 4th-A&B ] Instructions: Kindly provide the complete and correct solutions. (There are some questions that needs to be based in a periodic table, kindly base it on the one I provided below) I won't like it if it is incomplete and incorrect. 

 

PERIODIC TABLE OF THE ELEMENTS IA 1 H HA BA NA VIA 16 VIIA 17 1.01 2 VA 15 7 13 14 3 5 6 8 LI Be с 12.01 9.01 6.94 11 B 1081 13 Al Si 26.98 28.09 N 14.01 15 O 16.00 16 F 19.00 17 12 HIB IVB VB V16 VIIB V48 n 18 118 Na 22.99 19 Mg 24.31 3 4 5 6 7 8 9 10 11 12 20 21 22 23 24 25 26 20 29 Ca Sc Ti V Mn Fe 55.85 40.08 30 Cu Zn 63.55 65.39 47 44.96 47.87 K 39.10 37 Rb 85.47 50.94 54.94 CI 35.45 35 Br 79.90 53 1 27 Co 58.93 45 Rh Pd Ag Cd 102.91 106.42 107.87 112.41 Ni 58.69 46 30.97 32.07 31 34 Ga Ge Se 69.72 72.64 78.96 49 50 52 In Sn Sb Te 11482 118.71 121.76 127.60 126.90 As 74.92 51 38 Cr 52.00 42 Mo 95.94 74 39 40 48 Sr Y 88.91 Zr 91.22 87.62 56 Nb 92.91 73 Tc (98) 75 71 72 79 80 81 85 55 Cs Ba Lu 132.91 137.33 173.04 Hf Ta W Re Ru 101.07 76 77 76 Os Ir Pt 190.23 192.22 195.08 108 109 110 Hs Mt Ds (269) (278) (281) 82 Au Hg TI Pb 196.97 200.59 204.38 207.20 111 112 113 114 83 Bi 208.98 115 178.49 180.95 183.84 186.21 84 Po (209) 116 LV Uus (293) (294) At (210) 117 103 104 105 106 107 87 88 Fr Ra Lr Rf Sg Bh Db (268) Uup Rg Cn (280) Uut FI (286) (289) (223) (226) (262) (267) (269) (270) (285) (288) 57 58 59 60 61 62 66 Ce Lanthanide Series La 138.91 140.12 Pr Nd 140.91 144.24 Pm (145) 93 63 Sm Eu 150.36 151.96 67 68 69 Dy Ho Er Tm 162.50 164.93 167.26 168.93 70 Yb 173.04 64 65 Gd Tb 157.25 158.93 96 97 98 Cm Bk Cf (247) (247) (251) (252) 90 92 100 101 102 89 91 Ac Th Pa (227) 232.04 231.04 238.03 Actinide 95 Np Pu Am (237) (244) (243) 99 Es Fm Md No Senes (257) (258) (259) C F 18 2 He 4.00 10 Ne 20.18 18 Ar 39.95 36 Kr 83.80 54 Xe 131.29 96 Rn (222) 118 Uuo (294)
Transcribed Image Text:PERIODIC TABLE OF THE ELEMENTS IA 1 H HA BA NA VIA 16 VIIA 17 1.01 2 VA 15 7 13 14 3 5 6 8 LI Be с 12.01 9.01 6.94 11 B 1081 13 Al Si 26.98 28.09 N 14.01 15 O 16.00 16 F 19.00 17 12 HIB IVB VB V16 VIIB V48 n 18 118 Na 22.99 19 Mg 24.31 3 4 5 6 7 8 9 10 11 12 20 21 22 23 24 25 26 20 29 Ca Sc Ti V Mn Fe 55.85 40.08 30 Cu Zn 63.55 65.39 47 44.96 47.87 K 39.10 37 Rb 85.47 50.94 54.94 CI 35.45 35 Br 79.90 53 1 27 Co 58.93 45 Rh Pd Ag Cd 102.91 106.42 107.87 112.41 Ni 58.69 46 30.97 32.07 31 34 Ga Ge Se 69.72 72.64 78.96 49 50 52 In Sn Sb Te 11482 118.71 121.76 127.60 126.90 As 74.92 51 38 Cr 52.00 42 Mo 95.94 74 39 40 48 Sr Y 88.91 Zr 91.22 87.62 56 Nb 92.91 73 Tc (98) 75 71 72 79 80 81 85 55 Cs Ba Lu 132.91 137.33 173.04 Hf Ta W Re Ru 101.07 76 77 76 Os Ir Pt 190.23 192.22 195.08 108 109 110 Hs Mt Ds (269) (278) (281) 82 Au Hg TI Pb 196.97 200.59 204.38 207.20 111 112 113 114 83 Bi 208.98 115 178.49 180.95 183.84 186.21 84 Po (209) 116 LV Uus (293) (294) At (210) 117 103 104 105 106 107 87 88 Fr Ra Lr Rf Sg Bh Db (268) Uup Rg Cn (280) Uut FI (286) (289) (223) (226) (262) (267) (269) (270) (285) (288) 57 58 59 60 61 62 66 Ce Lanthanide Series La 138.91 140.12 Pr Nd 140.91 144.24 Pm (145) 93 63 Sm Eu 150.36 151.96 67 68 69 Dy Ho Er Tm 162.50 164.93 167.26 168.93 70 Yb 173.04 64 65 Gd Tb 157.25 158.93 96 97 98 Cm Bk Cf (247) (247) (251) (252) 90 92 100 101 102 89 91 Ac Th Pa (227) 232.04 231.04 238.03 Actinide 95 Np Pu Am (237) (244) (243) 99 Es Fm Md No Senes (257) (258) (259) C F 18 2 He 4.00 10 Ne 20.18 18 Ar 39.95 36 Kr 83.80 54 Xe 131.29 96 Rn (222) 118 Uuo (294)
2+ Based on the reaction, Sn + Cu²+ → Sn²+ + Cu* (in acidic medium) Calculate the following values: a. E cell [Identify which component is the cathode and anode, then look for their standard potential value and plug in the E^o]cell equation. A Table of Standard Electrode Potentials value can be found in the lecture slides; you may also search other additional or alternative preferences (make sure it is reliable). Some value may differ especially in the bird to fourth decimal places] b. AGⓇ [Use the standard cell potential value to solve the unknown.] c. K [Use the standard cell potential vale to solve the unknown.] d. E (when [Cu²+] = 0.0200 M, [Sn²+] = 0.0100 M, and [Cu] = 0.0300 M) [Use the Nernst Equation to solve for the potential at nonstandard conditions. Identify which values to input in the Q.]
Transcribed Image Text:2+ Based on the reaction, Sn + Cu²+ → Sn²+ + Cu* (in acidic medium) Calculate the following values: a. E cell [Identify which component is the cathode and anode, then look for their standard potential value and plug in the E^o]cell equation. A Table of Standard Electrode Potentials value can be found in the lecture slides; you may also search other additional or alternative preferences (make sure it is reliable). Some value may differ especially in the bird to fourth decimal places] b. AGⓇ [Use the standard cell potential value to solve the unknown.] c. K [Use the standard cell potential vale to solve the unknown.] d. E (when [Cu²+] = 0.0200 M, [Sn²+] = 0.0100 M, and [Cu] = 0.0300 M) [Use the Nernst Equation to solve for the potential at nonstandard conditions. Identify which values to input in the Q.]
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