1)A bottle of concentrated aqueous sulfuric acid, labeled 95.00 wt% H2SO4, has a concentration of 16.5 M. Calculate the density of 95.00 wt% H2SO4. 2)Ascorbic acid in 5 vitamin C tablets was measured by a titration against (100 ± 0.002 M) NaOH solution. It required 10.00 ± 0.05 mL NaOH solution to reach the equivalent point.
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1)A bottle of concentrated aqueous sulfuric acid, labeled 95.00 wt% H2SO4, has a concentration of 16.5 M. Calculate the density of 95.00 wt% H2SO4.
2)Ascorbic acid in 5 vitamin C tablets was measured by a titration against (100 ± 0.002 M) NaOH solution. It required 10.00 ± 0.05 mL NaOH solution to reach the equivalent point. What is the average quantity of ascorbic acid per vitamin tablet?
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- When a Vitamin C (ascorbic acid; MM = 176.12 g mol-1) tablet is crushed, dissolved and titrated with 0.0340 M KIO3(aq) to a purple/blue endpoint (given by a starch indicator), the volume of KIO3 used is 29.80 mL. If 60 mg of ascorbic acid is the recommended dietary allowance (i.e., 100% of the RDA), then what is the % RDA for the Vitamin C in the tablet? KIO3(aq) + 5 KI + 6 H+ → 3 I2(aq) + 3 H2O I2 (aq) + ascorbic acid → 2 I- + dehydroascorbic acid1. A solution is known to contain 38.04 ± 0.03 mM KCl, and you have taken an aliquot of this solution using a pipette calibrated to deliver 20.013 ±0.006 mL. Determine the number of moles of KCl that are delivered in the aliquot, including the absolute uncertainly in that value. 2. You deliver the aliquot taken in problem 1 into a volumetric flask with a volume of 250.00 mL ± 0.02 % and dilute the solution to volume in the flask using Dl water. What is the concentration of KCl in this flask, report your answer with the absolute uncertainty. 3. Tabulated below are replicate titration volumes for an analysis. What is the error (both absolute and percent) for the average titration volume?A 0.1475-M solution of Ba(OH)2 was used to titrate the acetic acid (60.05 g/mol) in a dilute aqueous solution. The following results were obtained. (See attached image)(a) Calculate the mean w/v percentage of acetic acid in the sample.(b) Calculate the standard deviation for the results.(c) Calculate the 90% confidence interval for the mean.(d) (d) At the 90% confidence level, could any of the results be discarded?
- Sixty mL of an impure acid solution was diluted to 500mL. A 30.00mL portion of this solution was titrated with 25.00mL of 0.1230M NaOH solution. Calculate the % (w/v) HAc in the sample. (FWt HAc = 60) Show all the solutions involved and round-off final answers to two decimal places except for Molarity. (Molar concentrations should be in four decimal places)Sample 1 2 3 4 Sample Volume, mL 50.00 49.50 25.00 50.00 Ba(OH)2 Volume, mL 43.17 42.68 21.47 43.33 A 0.1475-M solution of Ba(OH)2 was used to titrate the acetic acid (60.05 g/mol) in a dilute aqueous solution. The above results were obtained. 1. Calculate the mean w/v percentage of acetic acid in the sample 2. Calculate the standard deviation for the results. 3. Calculate the 90% confidence interval for the mean. 4. At the 90% confidence level, could any of the results be discarded?How much amount of solids (in grams) do you need to prepare the following solutions? 1. 500.0 mL 0.1000 M stock EDTA solutiona. Weigh an appropriate amount of Na2H2EDTA2H2O (FW=372.24) to the nearest 0.1 mg 2. 100.0 mL 0.0500 M stock Ca2+ solutiona. Weigh appropriate amount of pure CaCO3 (FW=100.09) to the nearest 0.1 mg into a 250 mL beaker.
- Six 50.0 ml volumetric flask 1 through 6 are labeled. 10.00 ml of 2.00 x 10-1 M Fe(NO3)3 solution was then pipet into each volumetric flask. A 1.00,2.00,3.00,4.00 and 5.00ml of 2.00 x 10-3M NaSCN solution was then pipetted to flask 2 through 6 respectively. A sufficient amount of 0.10 M nitric acid was then added to each flask to make each a total volume of 50.00ml. Hint M1V1=M2V2 a)what would be the concentration of Fe(NO3)3 in 0.10M HNO3? b)what would be the concentration of NaSCN in 0.10M HNO3?SO4 -two content in 7689mL of a water sample was precipitated as Na2SO4. The precipitated was filtered, washed and calcined in an empty crucible with a mass of 27.0234g. The mass of the crucible plus Na2SO4 (142g/mol) was 27.7708g. Calculate the %m/v of Na (23g/mol) and the concentration of Na in the sample in ppm.From a 1000 ppm stock solution of Pb2+, 10 mL are pipetted into a 1000 mL volumetric flask, which is then filled with water. From this new solution, 25 mL are pipetted into a 100 mL flask, which is then filled with water. What is the concentration of the final solution?
- A 25.00mL wastewater sample was analyzed for its Mg2+ content using a standard gravimetric method. the sample was diluted to 3.00L and an 11.00mL aliquot was treated to precipitate magnesium as MgNH4PO4.6H2O using (NH4)2HPO4 as the precipitating agent. the precipitate was then filtered, washed, dried, and ignited resulting in a 0.1325mg Mg2P2O7 residue. How much Mg (in ppm) is present in the original sample-3: A stock solution of 70% v/v ethanol was diluted with distilled water to prepare 1L of 21% v/v ethanol. (Density of ethanol = 0.789 g/mL; MW of ethanol = 46 g/mol) Determine the initial volume of 70% v/v ethanol used in the preparation. How much water was added to the stock solution to make 1L of the final concentration? The molarity of 5.0 mL of 70% v/v ethanol was found to be __________. Question 1-3: A stock solution of 70% v/v ethanol was diluted with distilled water to prepare 1L of 21% v/v ethanol. (Density of ethanol = 0.789 g/mL; MW of ethanol = 46 g/mol) Determine the initial volume of 70% v/v ethanol used in the preparation. How much water was added to the stock solution to make 1L of the final concentration? The molarity of 5.0 mL of 70% v/v ethanol was found to be __________.1.Determine the mass of sodium chloride required to prepare 400 ml of a Mueller-Hinton broth supplemented with 5.5% (wt/vol) sodium chloride solution. [Mwt NaCl = 58.44 g/mol] 2.Determine the mass of Fe(OH)3 that is required to prepare 350 ml of a 5N Fe(OH)3 solution. [Mwt Fe(OH)3 = 106.867g/mole]