17.28 From each equation and standard enthalpy, predict whether the reactior be spontaneous at all temperatures, spontaneous at low temperatures but nonspontaneous at high temperatures, nonspontaneous at low temperatures bi spontaneous at high temperatures, or not spontaneous at any temperature. Exj the reasons. (a) 2HgO(s) → 2Hg(1) + O2(g) AH® = 90.8 kJ (b) 4Fe(s) + 302(g) → 2Fe2O3(s) AH® = -1648.4 kJ

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter17: Chemcial Thermodynamics
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Problem 17.104QE: What is the sign of the standard Gibbs free-energy change at low temperatures and at high...
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17.28 From each equation and standard enthalpy, predict whether the reaction will
be spontaneous at all temperatures, spontaneous at low temperatures but
nonspontaneous at high temperatures, nonspontaneous at low temperatures but
spontaneous at high temperatures, or not spontaneous at any temperature. Explain
the reasons.
(a) 2HgO(s)
2Hg(l) + O2(g)
= 90.8 kJ
→
(b) 4Fe(s) + 302(g) → 2Fe2O3(s)
AH = -1648.4 kJ
(c) N2(g) + 3Cl2(g) → 2NC13(g)
днө — 460 kJ
作答
(d) 2NH4NO3(s) →
2N2(g) + 4H2O(g) + O2(g) AH® = -225.5 kJ
Transcribed Image Text:17.28 From each equation and standard enthalpy, predict whether the reaction will be spontaneous at all temperatures, spontaneous at low temperatures but nonspontaneous at high temperatures, nonspontaneous at low temperatures but spontaneous at high temperatures, or not spontaneous at any temperature. Explain the reasons. (a) 2HgO(s) 2Hg(l) + O2(g) = 90.8 kJ → (b) 4Fe(s) + 302(g) → 2Fe2O3(s) AH = -1648.4 kJ (c) N2(g) + 3Cl2(g) → 2NC13(g) днө — 460 kJ 作答 (d) 2NH4NO3(s) → 2N2(g) + 4H2O(g) + O2(g) AH® = -225.5 kJ
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