Please send me answer within 5 min!! I will rate you good for sure!! Please solve all the questions!! 17. One popular variation on theequal number of kernel threads but also allows amodel still multiplexes many user-level threads to a smaller orthread to be bound to a.......B. Many-to-many, kernel thread, user-levelD. Many-to-many, user-level, kernel threadE. Other:Consider a program that contains the following two threads. The threads are running concurrently, and x initialvalue is 0. Answer the following four questionsthreadl (0for (int 1-07 1<5; i++) (x= x + 1;System.out.print (x +A One-to-many, user-level, kernel threadC. Many-to-one, user-level, kernel thread18. The variables i and j are allocated inA Heap segmentC. Data segment19. The variable x is allocated inA. Heap segmentC. Data segment-");A 12357C. 13467thread2 () Ifor (int j 0; j<5; j++){xx 21System.out.print (x+ " ");1B. Process registersD. Thread registersE Other:B. Process registersD. Thread registersE. Other:20. The followings are possible outputs on the screen when i= 3 and j =2 exceptB. 12243D. 24567E. Other:

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17. One popular variation on the equal number of kernel threads but also allows a A. One-to-many, user-level, kernel thread C. Many-to-one, user-level, kernel thread Consider a program that contains the following two threads. The threads are running concurrently, and x initial value is 0. Answer the following four questions 18. The variables i and j are allocated in threadl (1 for (int i=0; i<5; i++) r x x + 1; -"); System.out.print (x + A Heap segment C. Data segment 19. The variable x is allocated in model still multiplexes many user-level threads to a smaller or thread to be bound to a....... B. Many-to-many, kernel thread, user-level D. Many-to-many, user-level, kernel thread E. Other: A. Heap segment C. Data segment A 12357 C. 13467 thread2 () 1 for (int j 0; j<5; j++){ x-x+ 21 System.out.print (x + " "); J B. Process registers D. Thread registers Other: E B. Process registers D. Thread registers E. Other: 20. The followings are possible outputs on the screen when i= 3 and j=2 except B. 12243 D. 24567 E. Other:

17. One popular variation on the equal number of kernel threads but also allows a A. One-to-many, user-level, kernel thread C. Many-to-one, user-level, kernel thread Consider a program that contains the following two threads. The threads are running concurrently, and x initial value is 0. Answer the following four questions 18. The variables i and j are allocated in threadl (1 for (int i=0; i<5; i++) r x x + 1; -"); System.out.print (x + A Heap segment C. Data segment 19. The variable x is allocated in model still multiplexes many user-level threads to a smaller or thread to be bound to a....... B. Many-to-many, kernel thread, user-level D. Many-to-many, user-level, kernel thread E. Other: A. Heap segment C. Data segment A 12357 C. 13467 thread2 () 1 for (int j 0; j<5; j++){ x-x+ 21 System.out.print (x + " "); J B. Process registers D. Thread registers Other: E B. Process registers D. Thread registers E. Other: 20. The followings are possible outputs on the screen when i= 3 and j=2 except B. 12243 D. 24567 E. Other:

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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My task from the teacher is to create a program that solves the three problems using threads in Python: 2 files: reader.py and writer.py In the readers-writers problem there is a common resource where a group of actors called readers want to read from the resource and another group of actors called writers want to write to the resource. The basic synchronization problem that needs to be solved is:1. Mutual exclusion of the resource, where:• only one writer may print at a time, and• no writer may write while a reader is reading.An ordinary mutex lock that is applied equally to all actors can solve this but will lead to only one actor being able to enter its critical section at a time. This is a problem as we normally want several readers to be able to read at the same time. The next problem that needs to be solved is therefore the following: 2. Several readers should be able to read the resource at the same time.In a solution where several readers can read simultaneously and lock out…
Question My task from the teacher is to create a program that solves the three problems using threads in Python: In the readers-writers problem there is a common resource where a group of actors called readers want to read from the resource and another group of actors called writers want to write to the resource. The basic synchronization problem that needs to be solved is:1. Mutual exclusion of the resource, where:• only one writer may print at a time, and• no writer may write while a reader is reading.An ordinary mutex lock that is applied equally to all actors can solve this but will lead to only one actor being able to enter its critical section at a time. The next problem that needs to be solved is therefore the following: 2. Several readers should be able to read the resource at the same time. The last problem that needs to be solved is therefore the following: 3. As soon as a writer wants to write, new readers must not enter their critical section.1 Use the threading module…
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Question My task from the teacher is to create a program that solves the three problems using threads in Python: In the readers-writers problem there is a common resource where a group of actors called readers want to read from the resource and another group of actors called writers want to write to the resource. The basic synchronization problem that needs to be solved is:1. Mutual exclusion of the resource, where:• only one writer may print at a time, and• no writer may write while a reader is reading.An ordinary mutex lock that is applied equally to all actors can solve this but will lead to only one actor being able to enter its critical section at a time. The next problem that needs to be solved is therefore the following: 2. Several readers should be able to read the resource at the same time. The last problem that needs to be solved is therefore the following: 3. As soon as a writer wants to write, new readers must not enter their critical section.1 Use the threading module…
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