17. An organic chemist reacted 10.0 g CH4 with excess Cl2 and obtained 10.0 g of CH3CI according to the following reaction: CH4C9) + Cl2(9) → CH;Cl(9) + HC(9) a. What should have been the theoretical yield? b. What was his percentage yield?

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Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.43PAE: 4.43 Magnesium nitride forms in a side reaction when magnesium metal burns in air. This reaction may...
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C = 12.01g/mol

H = 1.01g/mol

Cl = 35.45g/mol

17. An organic chemist reacted 10.0 g CH4 with excess Cl2 and obtained 10.0 g of CH3CI
according to the following reaction:
CH4(9) + Cl2(9) → CH3C(9) + HCl(9)
a. What should have been the theoretical yield?
b. What was his percentage yield?
Transcribed Image Text:17. An organic chemist reacted 10.0 g CH4 with excess Cl2 and obtained 10.0 g of CH3CI according to the following reaction: CH4(9) + Cl2(9) → CH3C(9) + HCl(9) a. What should have been the theoretical yield? b. What was his percentage yield?
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