16-6. Determine the support reactions at pins and 3. Take E = 200 GPa, I = 350(10) mm, A = 15(10³) mm² for each member. -2 m 60 kN -2 m- 2 2 3 4m
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- Part A A FA. FD= -600 mm- P 50 mm VE ΑΣΦ 41 B vec - 600 mm 25 mm If the gap between C and the rigid wall at D is initially 0.15 mm, determine the magnitudes of the support reactions at A and D when the force P = 200 kN is applied. The assembly is made of A36 steel. (Figure 1) Enter your answer, separated by a comma. -0.15 mm D ? kNThe bar AB has a built-in support at A. An external force F=6kN is applied at B (8,0,0)m, towards to point C (12,4,-2)m. Determine the reactions at A. O O O O O Rx=-4kN Ry=-4kN Rz=2kN Mx=16 kN-m My=16 kN-m Mz=32 kN m 8m Don't Know Rx=-4KN Ry=-4kN Rz=-4kN Mx=0 kN-m My=32 kN-m Mz=32 kN.m Rx=-4kN Ry=-4kN Rz=2kN Mx=0 kN.m My=16 kN-m Mz=32 kN m Rx=-4KN Ry=-4kN Rz=-4KN Mx=0 kN-m My=16 kN m Mz-32 kN.m F=6kN B(8,0,0) m *C(12,4,-2) m4-35 Determine compressive logds in members AB and Bc. FBD of B BC {Fy= 0 AB-160 AB/15 1601b AB = 3401bin E Fa= 0
- 3. At temperature T₁, the two rigidly connected rods just fit the rigid supports. If both sections are identical except for the diameter, prove that the following equations are true when temperature rises to T₂. a. F= b. OAB C. OBC A x(T₂-T₁)лd²E 20 x(T₂-T₁)E 5 9x(T₂-T₁)E 5 -1/2- d B 1/12- d C*4-20. The assembly consists of three titanium (Ti-6A1-4V) rods and a rigid bar AC. The cross-sectional area of each rod is given in the figure. If a force of 60 kip horizontal displacement of point F. is applied to the ring F, determine the AF-2 in² 1 ft 60 kip F-2 ft 2 ft E E 6 ft AAB-1 in² Acp-1.5 in² 6 ftFigure 4-26/27 Full Alternative Text *4-28. The rod has a slight taper and length L. It is suspended from the ceiling and supports a load P at its end. Show that the displacement of its end due to this load is 8 = PL/(TET ₂1). Neglect the weight of the material. The modulus of elasticity is E. Prob. 4-28 12. 11 P L
- 4-67. The assembly consists of a 15 mm nsod 250mm o loaulabo Probs. 4-65/66 6061-T6-aluminum nas a width of 200 mm and they are not bonded together. 750 mm Aluminum- Red brass 150 mm -75 mmThe two steel shafts (1) and (2) each Ø10 should be connected to each other with the help of the sleeve (3) (Øinner = 10, Øoutside = 15) also made of steel and two rivets at the points shown. The shaft (1) is firmly clamped on the left- hand side, the force F = 100 N acts on shaft 2 in the direction of the arrow. How are the brass round rivets to be dimensioned so that a safety of the coupling against failure of S = 10 is achieved? hole for rivets 1 F 3 a) What type of connection does a riveted connection have? b) What type of load does the rivet have? c) What is the diameter of the rivets? d) Which areas of the rivet are loaded? (Draw in figure and formula) e) Dimension the rivetProblem 2. The assembly consists of three titanium (Ti- 6A1-4V) rods and a rigid bar AC. The cross-sectional area of each rod is given in the figure. If a force of 6 kip is applied to the ring F, determine the horizontal displacement of point F, and determine the angle of tilt of rigid bar AC. B D 4 ft ACD = 1 in² AAB 6 ft 1.5 in² E 2 ft 1 ft 1 ft AEF = 2 in² 6 kip
- In the given figure, support A is a roller and support B is a pin support. If P=15 kips, calculate the 1) vertical reaction at A, 2) vertical reaction at B, 3) horizontal reaction at B P 6 kips 6 kips В 6 ft – 3 ft 2 ft ' 2 ftThe frame shown is supported by a pin at A and a fixed support at D. There are internal hinges/pins at and C. Assume P = 5 kips and w = 1 kip/ft. Determine all of the external support reactions. Clearly st true direction of each reaction. W 10 ft B -8 ft- D 2 ft 4 ft -PThe bar AB has a built-in support at A. An external force F=25kN is applied at B (5,6,1)m, towards to point C (5,2,4)m. Determine the reactions at A. Rx=0kN Ry=20kN Rz=-15kN Mx=-110 kN m My=75 kN.m Mz=100 kN-m Rx=25kN Ry=25kN Rz=25kN Mx=100 kN-m My=100 kN-m Mz=100 kN.m Rx=0kN Ry=20kN Rz=15kN Mx=110 kN-m My=75 kN-m Mz=100 kN-m Rx=0kN Ry=20kN Rz=15kN Mx=110 kN-m My=75 kN.m Mz=100 kN-m B (5, 6, 1) m F=25KN C (5, 2, 4) m