11.Complete the following nuclear equation: [2x2=4]92232 U → + 1 He642/029Cu->++12 + V

11.) 23292U is going under alpha decay so alpha particles will be removed from it mass number should…

Answered: 11. Complete the following nuclear…

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter10: Nuclear Physics

Section: Chapter Questions

Problem 4CQ: Why is the number of neutrons greater than the number of protons in stable nuclei that have an A...

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Similar questions

(a) Calculate the number of grams of deuterium in an 80.000L swimming pool, given deuterium is 0.0150% of natural hydrogen. (b) Find the energy released in joules if this deuterium is fused via the reaction 2H+2H3He+n. (c) Could the neutrons be used to create more energy? (d) Discuss the amount of this type of energy in a swimming pool as compared to that in, say, a gallon of gasoline, also taking into consideration that water is far more abundant.
Unreasonable Results The relatively scarce naturally occurring calcium isotope 48Ca has a halflife at about 21016y. (a) A small sample of this isotope is labeled as having an activity of 1.0 Ci. What is the mass of the 48Ca in the sample? (b) What is unreasonable about this result? (c) What assumption is responsible?
Integrated Concepts: (a) What temperature gas would have atoms moving fast enough to bring two 3He nuclei into contact? Note that, because both are moving, the average kinetic energy only needs to be half the electric potential energy of these doubly charged nuclei when just in contact with one another. (b) Does this high temperature imply practical difficulties for doing this in controlled fusion?
The purpose of producing 99Mo (usually by neutron activation of natural molybdenum, as in the preceding problem) is to produce 99mTc. Using the rules, verily that the decay of 99Mo produces 99mTc. (Most 99mTc nuclei produced in this decay are left in a metastable excited state denoted 99mTc.)
Why is the number of neutrons greater than the number of protons in stable nuclei that have an A greater than about 40? Why is this effect more pronounced for the heaviest nuclei?
(a) Calculate BE/A for 235U, the rarer of the two most common uranium isotopes. (b) Calculate BE/A for 238U. (Most of uranium is 238U.) Note that 238U has even numbers at both protons and neutrons. Is the BE/A of 238U significantly different from that of 235U?
The ceramic glaze on a red-orange “Fiestaware” plate is U2O3and contains 50.0 grams of 238U, but very little 235U. (a) What is the activity of the plate? (b) Calculate the total energy that will be released by the 238U decay, (c) If energy is worth 12.0 cents per kWh , what is the monetary value of the energy emitted? (These brightly- colored ceramic plates went out of production some 30 years ago, but are still available as collectibles.)
Data from the appendices and the periodic table may be needed for these problems. Unreasonable Results (a) Repeat Exercise 31.57 but include the 0.0055% natural abundance of 234U with its 2.45105y halflife. (b) What is unreasonable about this result? (c) What assumption is responsible? (d) Where does the 234U come from if it is not primordial?
How many kilograms of water are needed to obtain the 198.8 mol of deuterium, assuming that deuterium is 0.01500% (by number) of natural hydrogen?
(a) Neutron activation of sodium, which is 100% 23Na, produces 24Na, which is used in some heart scans, as seen in Table 32.1. The equation for the reaction is 23Na+n24Na+ . Find its energy output, given the mass of 24Na is 23.990962 u. (b) What mass at 24Na produces the needed 5.0mCi activity, given its halflife is 15.0 h?
(a) Calculate the energy released in the a decay of 238U . (b) What fraction of the mass of a single 238U is destroyed in the decay? The mass of 234Th is 234.043593 u. (c) Although the fractional mass loss is large for a single nucleus, it is difficult to observe for an entire macroscopic sample of uranium. Why is this?

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11. Complete the following nuclear equation: [2x2=4] 92 232 U → + 1 He 64 2/0 29 Cu-> + +12 + V