10/10 FIND STRESS IN Aluminum. IF E st= 200000 MPa, Ealu.=70000 .MPa 100 kN RALU=30 MM Aluminum Steel no one O 31 MPa O 69 MPa O 1m RST = 20 MM
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- A tensile test was performed on a metal specimen having a circular cross section with a diameter of 1 2 inch. The gage length (the length over which the elongation is measured) is 2 inches. For a load 13.5 kips, the elongation was 4.6610 3 inches. If the load is assumed to be within the linear elastic rang: of the material, determine the modulus of elasticity.A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/L =1392 kips/in. What is the modulus of elasticity?10:59 0.63 a. Y l KB/S VPN tutorial 1.pdf Axlal 1oads are applied to uie compounu rou inal is composeu of an aluminum segment rigidly connected between steel and bronze segments. (a) What is the stress in each material given that P = 10 kN? (b) Find the largest safe value of P if the working stresses are 120 MPa for steel, 68 MPa for aluminum, and 110 MPa for 2. Aluminum Steel A=300 mm² Bronze A=400 mm? A=600 mm² 2P 4P 3m -5m 4m bronze. Answer: a) 0one = 50 MPa; ouminum = 33.3 MPa; oel = 100 MPa ; b) P = 12KN A circular aluminum tube of length L = 400 mm is loaded in compression by axial forces P at the ends. The ou inside diameters are 60 mm and 50 mm, respectively. A strain gage is placed on the outside of the bar to measur strains in the longitudinal direction (axial direction). (a) If the measured compressive strain is ɛ = 550×10-6 , what is the shortening ô of the bar? (b) If the compressive stress in the bar is intended to be 40 MPa, what should be the load P? Answer: a) 8 = 0.22…
- 10/10 FIND STRESS IN Aluminum. IF E st= .200000 MPa, Ealu.=70000 MPa 100 kN RALU. 30 MM Aluminum Steel 1m RST 20 MM10/10 FIND STRESS IN Aluminum. IF E st= .200000 MPa, Ealu.=70000 MPa 100 kN RALU.=30 MM Aluminum Steel 55 MPа 19 MPa 69 MPa 31 MPa no one ( 1m RST 20 MM(40 How A Rismatic steel bar of a Square cro ss section (looxlo0)mm is loaoled by Compressive force P= 1300 K, the bar has length 2.5 m, Eg=200GPay V=0.3,determine the shortening 8, the increase in the dimensions of cross Section, the change in Volume DV of the bar? loomm loomm
- A high strength steel with modulus of elasticity of A N/mm', yield strength of B N/mm and crushing strength of C N/mm2 is used for a test. In the instance of crushing total strain was measured as D a) Find the ductility of steel. b) What should be the diameter of the bar to carry a load of E kN without any plastic deformation. A B D E 249000 1420 1660 2.90% 59Q5 A specimen of magnesium having a rectangular cross section of dimensions (3.2 mm X 19.1 mm) and gage length 63.5 mm is deformed in tension. Using the load-elongation data tabulated as follows load (N) and Extension (mm), Find the standard mechanical properties. load 1380 2780 5630 7430 8140 9870 12850 | 14100 14340 13830 12500 Ext. 0.03 0.06 0.12 0.2 0.25 0.64 1.91 3.18 4.45 5.72 6.99 a) Draw the stress strain curve. b) Find the young modulus. c) Find the proof stress d) Find the ultimate tensile strength. e) Find the fracture stress f) Find the maximum strain.10/10 FIND STRESS IN STEEL MATERIALS IN COMPOSITE COLUMIN SHOWN BELOW. IF E st= 200 kN/MM2, Ealu.=70 kN/MM2 100 kN RALU=30 MM Aluminum Steel 1m R ST 20 MM
- PROBLEM 1) An aluminum bar carries the axial loads at the positions shown. If E=70GPA, compute the total deformation of the bar. Assume that the bar is suitably braced to prevent buckling. 0.4m D 10KN 0.8m 0.4m 5KN 0.6m A 20KN 3) What is the deformation &cn in mm? A=800 mm? A=1,200 mm²Sample: Malleable Steel (AISI 4145) Original Diameter: 6.14mm Gauge Length: 55 mm Final Length: 68.12 mm Final Diameter: 3.54mm Load (kN) Deformation (mm) Stress (MPa) 12.95 Strain (%) 0.3838 0.54 0.7841 0.95 26.48 1.3899 1.63 1.9485 2.07 3.3090 3.10 4.5821 4.22 5.9359 5.03 7.0340 5.51 8.2413 6.22 10.9446 7.22 13.1951 8.18 12.8228 8.77 12.2583 9.11 12.5915 9.61 13.2536 10.33 13.6636 10.71 13.9772 11.35 14.5433 12.63 15.1155 13.88 15.4970 15.10 15.6484 17.09 15.4031 17.79 14.7655 18.73 13.6721 19.28 10.4617 19.88SITUATION. As shown in the figure below, a rigid bar with negligible mass is pinned at O and attached to two vertical rods. Assume that the rods were initially stress-free. Allowable stress in steel is 120 MPa and in bronze is 60 MPa. For this problem, a = 1.8m; b = 1.3m; c= 1.7m. a b I Bronze: A 1200 mm E83 GPa Lw2.0m What is the value of P Steel: A 900 mm E 200 GPa L=1.5m