100.0 mL of HCl required 25.00 mL of 0.2000 M NaOH to reach the end point. What is the concentration of the HCI? The neutralization equation is HCI + NaOH → NaCl + H₂O There is enough information to calculate the moles of NaOH L NaOH(- 1 L Then use stoichiometry to convert moles of NaOH into moles of HCI concentration = mol NaOH mol NaOH LHCI = mol HCI mol NaOH = We now can calculate the concentration of HCI since we have both the moles of HCI and the volume of HCI mol HCI mol NaOH mol/L mol HCI
100.0 mL of HCl required 25.00 mL of 0.2000 M NaOH to reach the end point. What is the concentration of the HCI? The neutralization equation is HCI + NaOH → NaCl + H₂O There is enough information to calculate the moles of NaOH L NaOH(- 1 L Then use stoichiometry to convert moles of NaOH into moles of HCI concentration = mol NaOH mol NaOH LHCI = mol HCI mol NaOH = We now can calculate the concentration of HCI since we have both the moles of HCI and the volume of HCI mol HCI mol NaOH mol/L mol HCI
Chapter9: Acids, Bases, And Salts
Section: Chapter Questions
Problem 9.99E
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