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- A least-squares regression line for a set of data with dependent variable y and independent variable x produces a 95% confidence interval [-0.5,1.8] on the regression slope (beta). We can conclude that: the predicted value of y for a given x will lie in the range [-0.5x,1.8x] 95% of the time the regression slope must be zero O beta will fall inside the range [-0.5,1.8] 95% of the time The data show no evidence of a linear relation between x and y O none of theseA random sample of 15 families representing three social classes has been observed for the frequency with which the parents administer physical punishment to the children over a period of a week. Are the differences significant? Use α = .05 and the five-step model to conduct your hypothesis test. Write a sentence or two interpreting your results. Working Class: 10,9,4,2,1 Middle Class: 11,10,5,2,0 Upper Class: 7,5,2,0,0The 98% confidence interval for the intercept, coefficient of X1, and coefficient of X2 of a linear model with 2 predictors, are (18, 24), (-2,9) and (-1, 3) respectively based on 33 samples. a) What are the t-stats for X1 and X2? b) Is the coefficient of X1 statistically more significant than that of X2?
- A)Test the claim, at the a = 0.10 level of significance, that a linear relation exists between the two variables, for the data below, given that y-1.885x + 0.758. Step 1) State the null and alternative hypotheses. Step 2) Determine the critical value for the level of significance, a. Step 3) Find the test statistic or P-value. Step 4) Will the researcher reject the null hypothesis or do not the null hypothesis? Step 5) Write the conclusion. B) The regression line for the given data is y = -1.885x + 0.758. Determine the residual of a data point for which x = 2 and y = -4. C) Give a practical interpretation of the coefficient of determination, R2. Express R2 to the nearest whole percent. HIML Editor SAMSUNG &Fifty students take two midterm exams. On the first exam, the mean score is 65.0 and the standard deviation is 7.00. On the second exam, the mean score is 55.0 with a standard deviation of 10.00. The correlation coefficient of the two score is 0.70. Obtain the least squares regression line using the second exam score to predict the first exam score.The data in the table below presents the hourly quantity of production for three lines of production processes over the first 4 days in XYZ Company. Answer the questions based on the Excel Output given in the picture below. State the null and alternative hypothesis for single factor ANOVA. State the decision rule (α = 0.05). Calculate the test statistic. Make a decision.
- Neurosurgery Operative Times. An Arizona State University professor, R. Jacobowitz, Ph.D., in consultation with G. Vishteh, M.D., and other neurosurgeons obtained data on operative times, in minutes, for both a dynamic system (Z-plate) and a static system (ALPS plate). They wanted to perform a hypothesis test to decide whether the mean operative time is less with the dynamic system than with the static system. a. identify the variable. b. identify the two populations. c. determine the null and alternative hypotheses. d. classify the hypothesis test as two tailed, left tailed, or right tailed.Minimization of false trends in measurement caused by extraneous variables can be minimized by: A. Randomizing the order of application of the independent variable. B. Repeated measurement of the dependent variables. C. Signal conditioning and recalibration of the test instrument. D. Neglecting controlled parametrization of fundamental features of the test instrument. E. Getting a new replacement of the test instrument.8)Suppose that Y is normal and we have three explanatory unknowns which are also normal, and we have an independent random sample of 11 members of the population, where for each member, the value of Y as well as the values of the three explanatory unknowns were observed. The data is entered into a computer using linear regression software and the output summary tells us that R-square is 0.86, the linear model coefficient of the first explanatory unknown is 7 with standard error estimate 2.5, the coefficient for the second explanatory unknown is 11 with standard error 2, and the coefficient for the third explanatory unknown is 15 with standard error 4. The regression intercept is reported as 28. The sum of squares in regression (SSR) is reported as 86000 and the sum of squared errors (SSE) is 14000. From this information, what is MSE/MST? .5000 NONE OF THE OTHERS .2000 .3000 .4000
- A manufacturer of a new medication on the market for Parkinson's disease makes a claim that the medication is effective in 75% of people who have the disease. One hundred fifty individuals with Parkinson's disease are given the medication, and 100 of them note the medication was effective. Does this finding provide statistical evidence at the 0.05 level that the effectiveness is less than the 75% claim the company made? Make sure to include parameter, conditions, calculations, and a conclusion in your answer.9)Suppose that Y is normal and we have three explanatory unknowns which are also normal, and we have an independent random sample of 11 members of the population, where for each member, the value of Y as well as the values of the three explanatory unknowns were observed. The data is entered into a computer using linear regression software and the output summary tells us that R-square is 0.79, the linear model coefficient of the first explanatory unknown is 7 with standard error estimate 2.5, the coefficient for the second explanatory unknown is 11 with standard error 2, and the coefficient for the third explanatory unknown is 15 with standard error 4. The regression intercept is reported as 28. The sum of squares in regression (SSR) is reported as 79000 and the sum of squared errors (SSE) is 21000. From this information, what is the adjusted R-square? .8 .7 NONE OF THE OTHERS .6 .5
