1.4 4 (a) Calculate the value of Ke for the reaction: PCls ( PC13 (8) + Cl2 (g) AH Positive Given that when 8.4 mol of PCls (g) is mixed with 1.8 mol of PC13 (g) and allowed to come to equilibrium in a 10 dm³ container the amount of PCls (g) at equilibrium is 7.2 mol. Kc = (b) Explain the effect of the following changes below on the value of Kc: (i) Increasing temperature (ii) Lowering the concentration of chlorine (Cl₂) (iii) Addition of a catalyst

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.78PAE
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7
4 (a) Calculate the value of Kc for the reaction:
PC15 (2)
PC13 (g) + Cl2 (g)
AH = Positive
Given that when 8.4 mol of PCls (g) is mixed with 1.8 mol of PC13 (g) and allowed to come to equilibrium in a 10
dm³ container the amount of PCls (g) at equilibrium is 7.2 mol.
Kc =
(b) Explain the effect of the following changes below on the value of Kc:
(1)
Increasing temperature
(ii)
Lowering the concentration of chlorine (Cl2)
(iii)
Addition of a catalyst
Transcribed Image Text:7 4 (a) Calculate the value of Kc for the reaction: PC15 (2) PC13 (g) + Cl2 (g) AH = Positive Given that when 8.4 mol of PCls (g) is mixed with 1.8 mol of PC13 (g) and allowed to come to equilibrium in a 10 dm³ container the amount of PCls (g) at equilibrium is 7.2 mol. Kc = (b) Explain the effect of the following changes below on the value of Kc: (1) Increasing temperature (ii) Lowering the concentration of chlorine (Cl2) (iii) Addition of a catalyst
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