1.18 The static equilibrium position of a massless rigid bar, hinged at point O and connected with springs k, and k2, is shown in Fig. 1.74. Assuming that the displacement (x) resulting from the application of a force Fat point A is small, find the equivalent spring constant of the sys- tem, ke that relates the applied force F to the displacement x as F = kx k = 2k k2= k FIGURE 1.74 Rigid bar connected by springs. /2

1.18 The static equilibrium position of a massless rigid bar, hinged at point O and connected with springs k, and k2, is shown in Fig. 1.74. Assuming that the displacement (x) resulting from the application of a force Fat point A is small, find the equivalent spring constant of the sys- tem, ke that relates the applied force F to the displacement x as F = kx k = 2k k2= k FIGURE 1.74 Rigid bar connected by springs. /2

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

(2.14) For the system shown in Figure P2.14, the displacements x₁ and x2 are measured relative to M3. Both springs are undeflected when x1 = x2 = 0. Draw free-body diagrams and write the modeling equations. 0000 X1 M₁ XXXXXXB₁ K₁ -000 M3 M₂ B₂xxxxxx Figure P2.14 x2 K2₂ 000 777 -fa(t)
1.20 Figure 1.76 shows a uniform rigid bar of mass m that is pivoted at point O and connectedby springs of stiffnesses k1 and k2. Considering a small angular displacement u of the rigidbar about the point O, determine the equivalent spring constant associated with the restoringmoment. Use equivalent potential energy to solve.
Problem No 6 1.26 Find the equivalent spring constant of the system shown in Fig. 1.82. k F k k k FIGURE 1.82 Springs connected in series-parallel
igure 2. Assume that the rod is massless, perfectly rigid, and pivoted at point P. When the rod is perfectly horizontal, the angle 0 = 0, the displacement y 0, and the springs are in neither tension nor compression. Gravity acts on the system (e.g. on mass M). We assume that y is a small displacement. A mass M is attached at the end of the rod. DE only 225 Your tasks: X k 0 3k a F a M y A Derive an equation of motion for the system in terms of the angular displacement 0, and its derivatives (you should not have y or its derivatives in this equation.) B Derive an equation of motion for the system in terms of the displacement y, and its derivatives (you should not have or its derivatives in this equation. C Assuming there is no external actuator force F acting on the system, write down the total energy H of the system in terms of 0,0 and element constants. Derive an expression for the time derivative H of the total energy. D Transform the equation from part B, which is in y, to another…
I need your help expert. The system shown below is in equilibrium. Spring 3 is known to have a change in length of 10 cm. The magnitude of the compressive force in Spring 2 is 15% more than the magnitude of force P, while the magnitude of the compressive force in Bar 1 is 100 N less than that in Spring 2. If the spring constants of Springs 2 and 3 are 625 and 1200 N/m, respectively, determine the following: a. magnitude of forces P (in N) and F (in N) b. tension (in N) in cable ABC c. mass (in kg) of Block A d. compressive force in Bar 1 e. change in length (in cm) of Spring 2 Draw the complete FBD’s of Block A, Hook C and Pulley E. (Note: Below are the final answers, kindly match your answer on this. Thank you) Answer: P = 131.2831 N, F = 87.1569 N, TABC = 110.7024 N, mA = 15.6338 kg, F1 = 50.9756 N, s2 = 24.1561 cm
An ideal spring, with a pointer attached to its end, hangs next to a scale. With a 100 N weight attached, the pointer indicates "40" on the scale as shown. Using a 200N weight instead results in "60" on the scale. Using an unknown weight X results in "30" on the scale. The weight X is: Hint: Draw the force - Displacement diagram. 100 N O 1.20 N O 2.30 N O 3.40 N O 4.50 N O 5.70 N
5. Find the equivalent spring constant of the system shown in Fig. 1.85 in the direction of the load P. kg K8 03 KA k3 k2 FIGURE 1.85
A rod 8 meters long and weighing 200 N is circular from the left end of the wall.It is fixed to move. The other end is connected to the same wall from above via cable.fixed. There is a 53 degree angle between the rod and the cable (Zone 2). Man weighing 800 Nstand 92 cm from the wall, the tension in the rope is the magnitude of the force the wall exerts on the rod.and find its direction. Draw the free body diagram of the system.
Problem No 5 1.9 In Fig. 1.69, find the equivalent spring constant of the system in the direction of 0. k2 k3
Damian’s car weighs 2000kg. The spring has a natural unstretched length of 2m and a spring constant of k = 80000N/m. Hooke's law can be written as T = kd. Where T is the tension force in newtons, k is the spring constant and d is the length in metres. Let x(t) be the position of the front of Damian’s car and let y(t) be the position of the back of Eva’s 4WD. We will assume that the position of Eva’s car is a known function of time. Q1 a) Create a sketch of the positions of the vehicles similar to the one given and add the positions x and y. b) What is the extension of the spring in terms of x(t) and y(t)? Be careful to take into account that the unstretched length of the spring is 2m.
4. A uniform ladder 10m long and weighing 350N rests against a smooth wall at an angle of 30° with the wall. A 700N man stand 6m up from the bottom of the ladder. Find the horizontal force necessary at the base to keep the ladder from slipping.
k, k3 A В k2 What is the equivalent spring stiffness between the points A and B. If ki = 1 N/m, k2 =1 N/m. k3 = 2 N/m and k4 = 2 N/m A N/m