1. Real-life heat Capacity is temperature dependent. Consider the formation of water vapor H2(g)+( ½)O2(g) → H20(g) The heat capacities Cp(T) for each of the reactants and the product is given by Cp=a+bT+CT 2 where the constants a, b and c depend on the substance. The above equation is valid from 298 K to 2,000 K. a. The units of a, b and c are .? b. Calculate AH given (298 K)=-60kCal. Express your answers in terms of a, b, c for the reactants and products (aH2, bH2 --) (Answers choices for part b) AH (T) = -60kCal AH (T) = -60kCal + (aH,0 – an, – ļa0,) (T – 298K) + 4 (b,0 – bu, – įbo.) (T² – 298° K²) – (cH,0 – CH, – ¿co,) († - AH (T) = (an,0 – a, – ža0,) (T – 298K) + (bn,0 – bu, – įbo,) (Tª – 298° K²) – (c1,0 – en, – įco,) († - *K) 208K O AH (T) = -60kCal – (an,0 – an, – ža0,) (T – 298K) – † (bH,0 – bu, – įbo,) (Tª – 298° K²) + (cH,0 – cH, – ļco.) († - )

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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.132QP
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1. Real-life heat Capacity is temperature dependent. Consider the formation of water vapor H2(g)+(
)O2(g) → H20(g) The heat capacities Cp(T) for each of the reactants and the product is given by
Cp-a+bT+CT2 where the constants a, b and c depend on the substance. The above equation is
valid from 298 K to 2,000 K.
a. The units of a, b and c are . ?
b. Calculate AH given (298 K)=-60kCal. Express your answers in terms of a, b, c for the reactants and
products (aH2, bH2 --)
(Answers choices for part b)
дН (T) — — 6оCal
O AH (T) = -60kCal + (aH,0 – aĦ, – ļa0.) (T – 298K) + 4 (b#,0 – bH, – įbo.) (T² – 298° K²) – (CH,0 – CH, – țco.) (+ - )
AH (T) = (an,0 – an, – 40,) (T – 298K) + (bn,0 – bn, – bo;) (T² – 298° K²) – (cH,0 – CH, - co,) (- K)
Ο ΔΗ (T)ε
= -60kCal – (aH,0 – a#, - }a0.) (T – 298K) – | (bH,0 – bH, - bo.) (T² – 298° K²) + (cH,0 – CH, - co.) ( - K)
Transcribed Image Text:1. Real-life heat Capacity is temperature dependent. Consider the formation of water vapor H2(g)+( )O2(g) → H20(g) The heat capacities Cp(T) for each of the reactants and the product is given by Cp-a+bT+CT2 where the constants a, b and c depend on the substance. The above equation is valid from 298 K to 2,000 K. a. The units of a, b and c are . ? b. Calculate AH given (298 K)=-60kCal. Express your answers in terms of a, b, c for the reactants and products (aH2, bH2 --) (Answers choices for part b) дН (T) — — 6оCal O AH (T) = -60kCal + (aH,0 – aĦ, – ļa0.) (T – 298K) + 4 (b#,0 – bH, – įbo.) (T² – 298° K²) – (CH,0 – CH, – țco.) (+ - ) AH (T) = (an,0 – an, – 40,) (T – 298K) + (bn,0 – bn, – bo;) (T² – 298° K²) – (cH,0 – CH, - co,) (- K) Ο ΔΗ (T)ε = -60kCal – (aH,0 – a#, - }a0.) (T – 298K) – | (bH,0 – bH, - bo.) (T² – 298° K²) + (cH,0 – CH, - co.) ( - K)
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