1. Find the error in the given code: class Test { public static void main(String args[]) { System.out.println (fun()); static int fun () { static int x= 10; return x--; Also, are static local variables allowed in Java?
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ASAP!!
![1. Find the error in the given code:
class Test {
public static void main (String args []) {
System.out.println (fun ());
}
static int fun ()
{
static int x= 10;
return x--;
}
Also, are static local variables allowed in Java?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72f7ea79-67a9-4221-a752-ad62a5bf9047%2Fa9ee4056-6cf3-4189-99ae-004de83ad749%2Fp7pc5xj_processed.png&w=3840&q=75)
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- class class { public static void main(String args[]) { int a =5; int b =10; first: { second: { third: { if(a == b >>1) break second; } System.out.println(a); } System.out.println(b); } } } Give result for the code Java Try to do ASAPclass Output{public static void main(String args[]){int x = 3.14;int y = (int) Math.abs(x);System.out.print(y);}} The output of the above Java code is ?light } What is the output of this Java program? } class Driver { public static void main(String[] args) { int a = 6: int b = 6; int c = 5; int x = 1; if (a > 2) { } } if x = x + 600; (b> 3) { x = x + 60; } if (c < 9) { X = x + 5; System.out.print(x);
- class Output{public static void main(String args[]){Integer i = new Integer(557);float x = i.floatValue();System.out.print(x);}} What will the given code prints on the output screen.True or False A Java method can be defined to accept a varying number of parameters.10. public static void methodl (int i, int num) { for (int j = 1; j <= i; j++) { " "); System.out.print (num + num *= 2; } System.out.println(); } public static void main(String[] args) { int i = 1; while (i <= 6) { methodl (i, 2); i++; }
- using System;class Program{ public static void Main(string[] args) { int number = 1; while (number <= 1000) { Console.WriteLine(number); number = number + 1; } }} how would i add an if statement to this code? any if statement would workpublic class Test { } public static void main(String[] args) { String str = "Salom"; System.out.println(str.indexOf('t)); }fix the error of the program below. class Buku{ int a = 10; String b = "Buku Baru"; public static void main(String args[]) { System.out.println("i:"+a); System.out.println("s:"+b); } }
- Analyse the following code. public class Test { int x; public Test(String t) { System.out.println("Test"); } public static void main(String[] args) { Test test = new Test(); System.out.println(test.x); } } A. The program has a compile error because you cannot create an object from the class that defines the object. B. The program has a compile error because System.out.println method cannot be invoked from the constructor. C. The program has a compile error because x has not been initialized. D. The program has a compile error because Test does not have a default constructor.class main { public static void main(String args[]) { int x =2; int y =0; for(; y <10;++y) { if(y % x ==0) continue; elseif(y ==8) break; else System.out.print(y +" "); } } } Give result for the code Java Try to do ASAPof code and give their exact output with the tracing steps.